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Slav-nsk [51]
3 years ago
15

A parallel-plate capacitor has area A and plate separation d, and it is charged to voltage V. Use the formulas from the problem

introduction to obtain the formula for the energy U of the capacitor
Physics
1 answer:
Shtirlitz [24]3 years ago
3 0

Answer:

U = (ε0AV^2) / 2d

Explanation:

Where C= capacitance of the capacitor

ε0= permittivity of free space

A= cross sectional area of plates

d= distance between the plates

V= potential difference

First, the capacitance of a capacitor is obtained by:

C = ε0A/d.

Starting at the formula , U= (CV^2)/2. Formula for energy stored in a capacitor

Substitute in for C:

U = (ε0A/d) * V^2 / 2

Hence:

U = (ε0AV^2) / 2d

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Lady_Fox [76]

Answer:

\boxed{a = 0.2 m/s^2}

Explanation:

<u><em>Given:</em></u>

Force = F = 10 N

Mass = m = 50 kg

<u><em>Required:</em></u>

Acceleration = a = ?

<u><em>Formula:</em></u>

F = ma

<u><em>Solution:</em></u>

For a, the formula will be:

=> a = F/m

=> a = 10/50

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In a dense core called the nucleus

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3 years ago
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6 0
2 years ago
What is the impulse of a 3 kg object that starts from rest and moves to 20 m/s?
IrinaK [193]

Answer:

The impulse on the object is 60Ns.

Explanation:

Impulse is defined as the product of the force applied on an object and the time at which it acts. It is also the change in the momentum of a body.

F = m a

F = m(\frac{v_{2}  - v_{1} }{t})

⇒     Ft = m(v_{2} - v_{1})

where: F is the dorce on the object, t is the time at which it acts, m is the mass of the object, v_{1} is its initialvelocity and v_{2} is the final velocity of the object.

Therefore,

impulse = Ft = m(v_{2} - v_{1})

From the question, m = 3kg, v_{1} = 0m/s and v_{2} = 20m/s.

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8 0
3 years ago
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