Explanation:
Given parameters:
Initial velocity = 72km/hr
Final velocity = 0km/hr
Time taken = 25s
Unknown:
Acceleration = ?
Solution:
To solve this problem, convert km/hr to m/s;
1000m = 1km
3600s = 1hr
72km/hr;
1km/hr = 0.278m/s
72km/hr = 0.278 x 72 = 20.02m/s
Acceleration is the change in velocity divided by the time taken;
Acceleration =
Acceleration = = -0.8m/s
The car is actually decelerating at a rate of 0.8m/s
time should you wait between pushes is 2.83 sec.
the question is incomplete, full statement is-
A 24 kg child sits on a 2.0-m-long rope swing. You are going to give the child a small, brief push at regular intervals. If you want to increase the amplitude of her motion as quickly as possible, how much time should you wait between pushes?
<h3>What is Amplitude?</h3>In physics, amplitude refers to the greatest displacement or distance that a point on a vibrating body or wave may move relative to its equilibrium location. It is equivalent to the vibration path's half-length.
regular interval - at similarly spaced intervals: having the same interval of time between occurrences From 4 a.m. to midnight, the buses operate at regular intervals. The boards are positioned at regular intervals, with an equal amount of space between each.
The length of swing, l = 2.1 m
The time between the pushes is nothing but the Time period
and is given by the formula,
= 2 * 3.14 ( 2.0/ 9.8 ) ^ (1/2)
= 2.83 sec
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The grandfather clock will now run slow (Option A).
<h3>What is Time Period of an oscillation?</h3>Now,
Hence, the grandfather clock will now run slow (Option A).
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