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Slav-nsk [51]
3 years ago
15

A parallel-plate capacitor has area A and plate separation d, and it is charged to voltage V. Use the formulas from the problem

introduction to obtain the formula for the energy U of the capacitor
Physics
1 answer:
Shtirlitz [24]3 years ago
3 0

Answer:

U = (ε0AV^2) / 2d

Explanation:

Where C= capacitance of the capacitor

ε0= permittivity of free space

A= cross sectional area of plates

d= distance between the plates

V= potential difference

First, the capacitance of a capacitor is obtained by:

C = ε0A/d.

Starting at the formula , U= (CV^2)/2. Formula for energy stored in a capacitor

Substitute in for C:

U = (ε0A/d) * V^2 / 2

Hence:

U = (ε0AV^2) / 2d

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babunello [35]

Answer:

While a body is said to be in motion if it changes its position with respect to immediate surroundings.

A body is said to be in uniform motion if it covers equal distances in equal interval of time.

A body is said to be in non-uniform motion if it covers unequal distances in equal interval of time or vice-versa

4 0
2 years ago
How large amount of energy is produced during the fission of uranium ​
vova2212 [387]

Answer:

answer is a very large amount of energy is produced from a very small mass

Explanation:

nuclear energy is produced either by fusion or fission the former is fusion of lighter atoms into heavier elements while the letter is the splitting of a heavier atom into lighter atoms. both produce tremendous amount of energy fusion causes compassion of mass wild fission reduces it. and produce it. fusion does not produce radioactive particles while fission does (alpha and beta particles and neutrons)

4 0
3 years ago
What happens when an atoms losses an electron-
inysia [295]
It becomes positive
8 0
3 years ago
A boy throws a stone straight upward with an initial
Dominik [7]

Answer:

14.8m

Explanation:

Given parameters:

Initial speed  = 17m/s

Unknown:

Maximum height  = ?

Solution:

At the maximum height, the final speed will be 0m/s;

 We use of the kinematics equation to solve this problem.

     V²   = U²   - 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

         0²   = 17²  -  (2  x 9.8 x h )

          0 = 289  - (9.6h)

         -289  = -19.6h

            h  = 14.8m

5 0
3 years ago
During an adiabatic process an object does 100 J of work and its temperature decreases by 5 K. During another process it does 25
Liono4ka [1.6K]

Answer:

The heat capacity for the second process is 15 J/K.

Explanation:

Given that,

Work = 100 J

Change temperature = 5 k

For adiabatic process,

The heat energy always same.

dQ=0

dU=-dW

We need to calculate the number of moles and specific heat

Using formula of heat

dU=nC_{v}dT

nC_{v}=\dfrac{dU}{dT}

Put the value into the formula

nC_{v}=\dfrac{-100}{5}

nC_{v}=-20\ J/K

We need to calculate the heat

Using formula of heat

dQ=nC_{v}(dT_{1})+dW_{1}

Put the value into the formula

dQ=-20\times5+25

dQ=-75\ J

We need to calculate the heat capacity for the second process

Using formula of heat

dQ=nC_{v}(dT_{1})

Put the value into the formula

-75=nC_{v}\times(-5)

nC_{v}=\dfrac{-75}{-5}

nC_{v}=15\ J/K

Hence, The heat capacity for the second process is 15 J/K.

5 0
4 years ago
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