The Specific Heat Capacity of the liquid is 43.846 KJ/(Kg K).
- It is given that Mass of liquid (M) = 0.0012Kg, Initial temperature (T1) = 23°C, Final temperature (T2) = 62°C, Voltage (V) = 8v, Current (I) = 0.95A, Time (t) = 270s
- The quantity of heat that must be applied to an object in order to cause a unit change in temperature is known as the heat capacity or thermal capacity of that object.
- We know that heat capacity for a substance is :
- H = m*C*ΔT - equation (1)
- When a conductor is subjected to current flow, the conductor's free electrons are set in motion and collide with one another. Moving electrons experience kinetic energy loss and partial thermal energy conversion as a result of the collision. This impact of current is referred to as its heating effect.
- Due to electric current, heat energy is :
- H = Power * Time
- H = Current * Voltage * Time
- H = I*V*t - equation (2)
- Using equation (1) and (2),
- m*C*ΔT = I*V*t
- Substituting the values for m, ΔT, I, V and t.
- 0.0012Kg * C * (62 - 23)K = 0.95A * 8v * 270s
- Solving for C, we get C = 43.846 KJ/(Kg K)
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Answer:
T1 cos 15 = T2 cos 26
T1 = T2 cos 26 / cos 15
T1 = 0.930 T2 ------------(1)
T1 sin 15 + T2 sin 26 = m g
substitute eqn(1)
(0.930 T2 ) sin 15 + T2 sin 26 = 230 * 9.8
0.241 T2 + 0.438 T2 = 2254
Tension in right cable T2 = 3319 N
substitute in eqn (1)
T1 = 0.930 * 3319
Tension in left cable T1 = 3087
There is not enough information given tl be able to solve this problem
Ultraviolet rays.
The sun emits UV rays which reach the earth by radiation, heats the earth. The harmful rays are reflected back.
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Complete question:
The 100-kg homogeneous cylindrical disk is at rest when the force F =500N is applied to a cord wrapped around it, causing the disk to roll. Use the principle of work and energy to determine the angular velocity of the disk when it has turned one revolution (radius of the disk = 300mm).
Answer:
The angular velocity of the disk when it has turned one revolution is 16.712 rad/s
Explanation:
From the principle of work and energy;
U = E₂ - E₁, since the disk is initially at rest, T₁ = 0
U = E₂
Work done, U = product of force and perpendicular distance
U = F × d
As the cord winds, force act through the cord at a distance of 2d
U = F × 2d
Distance of one complete revolution = 2πR = 2π(0.3) = 0.6π
U = 500 × 2(0.6π) = 1885.2 J
Kinetic energy E₂ 
![E_2 = \frac{1}{2}[(\frac{1}{2}mR^2)\omega^2] + \frac{1}{2}m(\omega R)^2\\\\E_2 = \frac{1}{2}[(\frac{1}{2}*100*0.3^2)\omega^2] +\frac{1}{2}*100(\omega)^2*0.3^2\\\\E_2 = 2.25 \omega^2 +4.5 \omega^2\\\\E_2 = 6.75 \omega^2](https://tex.z-dn.net/?f=E_2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5B%28%5Cfrac%7B1%7D%7B2%7DmR%5E2%29%5Comega%5E2%5D%20%2B%20%5Cfrac%7B1%7D%7B2%7Dm%28%5Comega%20R%29%5E2%5C%5C%5C%5CE_2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5B%28%5Cfrac%7B1%7D%7B2%7D%2A100%2A0.3%5E2%29%5Comega%5E2%5D%20%2B%5Cfrac%7B1%7D%7B2%7D%2A100%28%5Comega%29%5E2%2A0.3%5E2%5C%5C%5C%5CE_2%20%3D%202.25%20%5Comega%5E2%20%2B4.5%20%5Comega%5E2%5C%5C%5C%5CE_2%20%3D%206.75%20%5Comega%5E2)
Recall that U = E₂
1885.2 = 6.75ω²
ω² = 1885.2/6.75
ω² = 279.2889
ω = √279.2889
ω = 16.712 rad/s
Therefore, the angular velocity of the disk when it has turned one revolution is 16.712 rad/s
