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3 years ago

Earth receives energy from the sun through what method of heat transfer?

Physics

2 answers:

Daniel [21]3 years ago

4 0

Radiation that comes from the sun is being beemed at earth atmosphere

zimovet [89]3 years ago

3 0

Answer:

The answer is Radiation.

Explanation:

The phenomenon of radiation is the propagation of energy in the form of electromagnetic waves or subatomic particles through vacuum or a material medium. Solar radiation is the set of electromagnetic radiation emitted by the Sun and which reach the earth, although not all radiation reaches the Earth's surface, because the shortest ultraviolet waves are absorbed by the gases of the atmosphere. The magnitude that measures the solar radiation that reaches the Earth is the irradiance, which measures the power that per unit of surface reaches the Earth.

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an immersion heater rated 2.0A,240V is used to boil water from temperature 52°c to hundred°c. if the mass of the water is 2.5kg,

Leviafan [203]

Answer:

1.05 x 103s

Explanation:

The answer to the question is 1.05 x 103s

8 0

2 years ago

How much kinetic energy does a system containing 3 moles of an ideal gas at 300 K possess? What is the heat capacity at constant

ElenaW [278]

Answer:

1. K.E = 11.2239 kJ ≈ 11.224 kJ

2. $C_{V} = 37.413 JK^{- 1}$

3. $Q = 10.7749 kJ$

Solution:

Now, the kinetic energy of an ideal gas per mole is given by:

K.E = $\frac{3}{2}mRT$

where

m = no. of moles = 3

R = Rydberg's constant = 8.314 J/mol.K

Temperature, T = 300 K

Therefore,

K.E = $\frac{3}{2}\times 3\times 8.314\times 300$

K.E = 11223.9 J = 11.2239 kJ ≈ 11.224 kJ

Now,

The heat capacity at constant volume is:

$C_{V} = \frac{3}{2}mR$

$C_{V} = \frac{3}{2}\times 3\times 8.314 = 37.413 JK^{- 1}$

Now,

Required heat transfer to raise the temperature by $15^{\circ}$ is:

$Q = C_{V}\Delta T$

$\Delta T = 15^{\circ} = 273 + 15 = 288 K$

$Q = 37.413\times 288 = 10774.9 J = 10.7749 kJ$

8 0

3 years ago

A small box slides down a ramp on a friction with surface. If the total energy of the system is conserved, which computational m

spayn [35]

Answer:

WWWEEEEEEEEEEEEEEEEEE

Explanation:

6 0

3 years ago

Read 2 more answers

A 5.0-kg box is pulled by a horizontal force F applied to the top of the box. When the box meets a low doorstep, it begins to ro

NARA [144]

Answer:

the required minimum magnitude of the force F is 21 N

Explanation:

Given the data in the question,

m = 5 kg

width = 60 cm

height = 80 cm

Let force is F represent in the image below,

so when the block about to rotate normal shifted to edge of cube

mg(w/2) = Fh

F = mg(w/2) / h

we know that g = 9.8 m/s²

we substitute

F = (5 × 9.8 ( 60/2)) / 70

F = (5 × 9.8 × 30 ) / 70

F = 1470 / 70

F = 21 N

Therefore, the required minimum magnitude of the force F is 21 N

5 0

3 years ago

A 20 g ball of clay traveling east at 4.5 m/s collides with a 45 g ball of clay traveling north at 2.0 m/s. You may want to revi

german

Answer:

The ball travels with a speed of 1.96 m/s in a North East direction

Explanation:

Based on the law of conservation of linear momentum, we have that

$m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v$

Since this problem involves motion in both the x and y coordinates, we will solve it in the separate coordinates, and then find the resultant as our answer.

Momentum in the x- direction

in the x direction, $v_{2}= 0$ . this makes $m_{2}v_{2}=0$