Answer
given,
mass of disk = 2 Kg
radius = 0.1 m
time = 10 sec
a) 800 rpm to rad/s
=
=
b) 740 rpm to rad/s
=
=
c) Angular acceleration
d) moment of inertia of disc
I = 0.01 Kg.m²
e) τ = I α
τ = 0.01 x 0.629
τ = 6.29 x 10⁻³ N.m
f) impulse = Force x time
J = 0.629 Ns
g) Work done
W = Δ KE
W = 5.07 J
Answer:
0.381 m
Explanation:
Distance traveled S is found by
Where S is distance traveled, u is initial velocity, t is time, a is acceleration
Since we acceleration a is given as 60g, where g is gravitational constant of 9.81 then a=60*9.81=588.6
The initial velocity u is zero hence ut=0
Substituting a with 588.6, t with 36 ms
S=0.381 m
Answer:
The magintude of the acceleration for both objects is
Explanation:
Drawing a free body diagram on the two boxes we can analyze the system more easily.
we can take the acceleration going up as positive for reference purposes.
for mA let's suppose that is ascending so:
and for mB (descending):
because the two boxes has the same acceleration because they are attached together:
So the magintude of the acceleration for both objects is
Answer:
here's the pdf for it
IB QuestionbankExplanation:
Electrostatic force between two points in space is defined as,
The r is the distance between them.
So if,
Than,
Hope this helps.
r3t40