During upward projection the final velocity is zero, and the gravitational acceleration is -10 m/s² (against the gravity).
Therefore; using the equation;
S = 1/2gt² + ut
Where s is the height h, g is gravitational acceleration, and t is the time and u is the initial velocity u, is 16 ft/s.
Thus; h= 1/2(-10)t² + 16t
We get; h = -5t² + 16t
Therefore; the quadratic equation is 5t² - 16t + h =0
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Answer:
The required pressure is 6.4866 atm.
Explanation:
The given data : -
In the afternoon.
Initial pressure of tire ( p₁ ) = 7 atm = 7 * 101.325 Kpa = 709.275 Kpa
Initial temperature ( T₁ ) = 27°C = (27 + 273) K = 300 K
In the morning .
Final temperature ( T₂ ) = 5°C = ( 5 + 273 ) K = 278 K
Given that volume remains constant.
To find final pressure ( p₂ ).
Applying the ideal gas equation.
p * v = m * R * T
= 657.2615 Kpa = 6.486 atm
Answer:
Car has more power output than crane
Explanation:
We have given that mass of the crane m = 1000 kg
Height through which crane lift the steel beam h = 10 m
Acceleration due to gravity
So work done by crane
Time period is given as t = 5 sec
We know that power
Now mass of the car = 1000 kg
Initial velocity u = 0 m /sec
Final velocity v = 10 m/sec
We know that work done is equal to the change in kinetic energy
So work done
Time ids given as t = 2 sec
So power
So car has more power output than crane