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Sati [7]
3 years ago
6

Two point charges each experience a 1-N electrostatic force when they are 2 cm apart. If they are moved to a new separation of 8

cm, what is the magnitude of the electric force on each of them?
2 N

1/8 N

1/16 N

1/4 N

1/2 N
Physics
1 answer:
astraxan [27]3 years ago
3 0

Electrostatic force between two points in space is defined as,

F_e=\dfrac{Q_1Q_2}{4\pi r\epsilon_r\epsilon_0}

The r is the distance between them.

So if,

1N=\dfrac{Q_1Q_2}{4\pi 2cm\epsilon_r\epsilon_0}\Rightarrow 2\cdot1N=\dfrac{Q_1Q_2}{4\pi\cdot10^{-2}m\cdot\epsilon_r\epsilon_0}

Than,

\boxed{\dfrac{1}{4}N}=\dfrac{Q_1Q_2}{4\pi\cdot 8cm\cdot\epsilon_r\epsilon_0}\Rightarrow8\dfrac{1}{4}N\Leftrightarrow 2N=\dfrac{Q_1Q_2}{4\pi\cdot10^{-2}m\cdot\epsilon_r\epsilon_0}

Hope this helps.

r3t40

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Two boxes connected by a light horizontal rope are on a horizontal surface. The coefficient of kinetic fric-tion between each bo
babunello [35]

Answer:

(A). The tension in the rope that connects the boxes is 10.50 N.

(B). The value of m is 7 kg.

Explanation:

Given that,

Mass of box B = 5.00 kg

Mass of box A = m

Force = 40.0 N

Direction= 53.1°

Acceleration = 1.50 m/s²

Coefficient of kinetic friction = 0.30

(A). We need to calculate the tension in the rope that connects the boxes

Using balance equation

T=ma+m\cos\theta

Put the value into the formula

T=5\times1.50+5.00\cos53.1

T=10.50\ N

(B). We need to calculate the value of m

Using formula of tension

T=ma

m=\dfrac{T}{a}

Put the value into the formula

m=\dfrac{10.50}{1.50}

m=7\ kg

Hence, (A). The tension in the rope that connects the boxes is 10.50 N.

(B). The value of m is 7 kg.

3 0
3 years ago
The wires in a household lamp cord are typically 3.5 mm apart center to center and carry equal currents in opposite directions.
zhuklara [117]

Explanation:

It is given that,

Distance between wires, d = 3.5 mm = 0.0035 m

Power of light bulb, P = 100 W

Potential difference, V = 120 V

(a) We need to find the force per unit length each wire of the cord exert on the other. It is given by :

\dfrac{F}{l}=\dfrac{\mu_o I^2}{2\pi r}

Power, P = V × I

I=\dfrac{P}{V}=\dfrac{100}{120}=0.83\ A

This gives, \dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times (0.83)^2}{2\pi \times 0.0035}

\dfrac{F}{l}=0.0000393\ N/m

\dfrac{F}{l}=3.93\times 10^{-5}\ N/m

(b) Since, the two wires carry equal currents in opposite directions. So, teh force is repulsive.

(c) This force is negligible.

Hence, this is the required solution.

8 0
3 years ago
Part 1: A rope has one end tied to a vertical support. You hold the other end so that the rope is horizontal. If you move the en
Blizzard [7]

Answer:

c. 2 m/s

Explanation:

The speed of a wave is given by:

v=f \lambda

where

v is the speed of the wave

f is the frequency

\lambda is the wavelength

For the wave in this problem, we have

f = 4 Hz is the frequency

\lambda = 0.5 m is the wavelength

So, the speed of the wave is

v=(4 Hz)(0.5 m)=2 m/s

5 0
4 years ago
What is the speed of a wave that has a wavelength of 225 m and a frequency of 117 hz ? Show your work
avanturin [10]

Answer:

26325 m\s

Explanation:

Data:

v = ?

f = 117 Hz

w = 225

Formula:

v = fw

Solution:

v = ( 117)(225)

v = 26325 m\s <em>A</em><em>n</em><em>s</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

6 0
3 years ago
What two factors affect the gravitational force between two objects
Marina86 [1]

Answer:

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.Explanation:

7 0
3 years ago
Read 2 more answers
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