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3 years ago

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The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y - 4 =1/4(x-8). What is the slop

e - intercept form of the equation for this line?

1 answer:

Gelneren [198K]3 years ago

5 0

Answer:1/4

Step-by-step explanation:

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Andrei [34K]

Answer:

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2 years ago

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Find the zeros of the function g(x) = x2 - 6x - 16 by factoring. what is the largest zero of the function? enter a number only.

aleksandrvk [35]

(X-8)(x+2) is the factored equation. Ur zeros r -2 and 8. So the largest should be 8?

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3 years ago

Please Do These Three Equations And Show Work

german

2) Add 0.1 to both sides. v/2.2=7.5

Then multiply by 2.2 on both sides.

v=16.5

4) Subtract 1.9 from both sides. -1.3g=-13

Divide both sides by -1.3

g=10

6) Add 1.4 to both sides. -12.9=-3d

Divide -3 on both sides.

d=4.3

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2 years ago

What is W in this equation <br> -w–11≤w–5

zhannawk [14.2K]

Step-by-step explanation:

-w - 11 < or = w - 5

-2w - 11 < or = -5

-2w < or = -16

w > or = -8

5 0

3 years ago

BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

$3x=x+20$

$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

$m\angle ABC=(3x)^\circ+(x+20)^\circ$

$m\angle ABC=(4x+20)^\circ$

$m\angle ABC=(4(10)+20)^\circ$

$m\angle ABC=(40+20)^\circ$

$m\angle ABC=60^\circ$

Therefore, $m\angle DBC=30^\circ,m\angle ABD=30^\circ$ and $m\angle ABC=60^\circ$ .

8 0

2 years ago