The chemical formula CH2O can be classified as Empirical formula and possibly a molecular formula. The empirical formula of a compound is the simplest formula that indicates the simplest ratio of atoms in the compound, while the molecular formula is the representation of the actual whole number ratio between the elements of the compound.
Answer:
Ka = 1.39x10⁻⁶
Explanation:
A monoprotic acid, HX, will be in equilibrium in an aqueous medium such as:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
<em>Where Ka is:</em>
Ka = [H⁺] [X⁻] / [HX]
<em>Where [] is the molar concentration in equilibrium of each specie.
</em>
The equilibrium is reached when some HX reacts producing H+ and X-, that is:
[HX] = 1.64M - X
[H⁺] = X
[X⁻] = X
As pH is 2.82 = -log [H⁺]:
[H⁺] = 1.51x10⁻³M:
[HX] = 1.64M - 1.51x10⁻³M = 1.638M
[H⁺] = 1.51x10⁻³M
[X⁻] = 1.51x10⁻³M
And Ka is:
Ka = [1.51x10⁻³M] [1.51x10⁻³M] / [1.638M]
<h3>Ka = 1.39x10⁻⁶</h3>
Answer:
Molecular formula of aniline is C6H5NH2.
Explanation:
As we know, molecular mass can be calculated as
Molar mass = C6H5NH2
Molar mass = (6*12)+(1*7)+(28)
Molar mass = 93 g/mol
Hello there.
<span>Why are carbon and nitrogen essential for survival to all living organisms?
</span>
<span>They are needed to release the energy stored in food.
</span>Therefore, The correct answer would be Option B.
Answer:
Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).
Explanation:
Hello there!
In this case, according to the given redox reaction, we rewrite it as a convenient first step:

Next, we assign the oxidation numbers as follows:

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).
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