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Drupady [299]
3 years ago
14

Consider three identical flasks filled with different gases. Flask A: CO at 760 torr and 08C Flask B: N2 at 250 torr and 08C Fla

sk C: H2 at 100 torr and 08C
a. In which flask will the molecules have the greatest average kinetic energy?
b. In which flask will the molecules have the greatest root mean square velocity?
c. Which flask will have the greatest number of colli- sions per second with the walls of the container?
Chemistry
1 answer:
jonny [76]3 years ago
7 0

Answer:

a, b, c Flask B

Explanation:

The  root mean square velocity  of a gas is  given by

V = √ ( 3RT/M)

where m is the molar mass, T is the temperature of the gas and R is the gas constant.

Therefore we have that the the velocity of the gas molecules is  inversely proportional to the square root of the molar mass . That is the heavier the molecules the slower they will move which makes sense and the lower its kinetic energy.

The greater the velocity the more collisions the gas will  have against the walls of the container.

The molar mass of CO and N2 are 28 g/mol while H2 is 2 g/mol. Hence hydrogen the lightest  will have a greater kinetic enrgy, the greatest root mean square velocity and the greatest number of collisions with the wall of the container.

Notice that the pressure given for each is of the gases is different being the greatest for CO but pressure does not have an effect on the kinetic enery of the molecules.

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Can someone solve this for me I'm confused.
Artemon [7]

Answer:

310.53 g of Cu.

Explanation:

The balanced equation for the reaction is given below:

CuSO₄ + Zn —> ZnSO₄ + Cu

Next, we shall determine the mass of CuSO₄ that reacted and the mass Cu produced from the balanced equation. This can be obtained as follow:

Molar mass of CuSO₄ = 63.5 + 32 + (16×4)

= 63.5 + 32 + 64

= 159.5 g/mol

Mass of CuSO₄ from the balanced equation = 1 × 159.5 = 159.5 g

Molar mass of Cu = 63.5 g/mol

Mass of Cu from the balanced equation = 1 × 63.5 = 63.5 g

Summary:

From the balanced equation above,

159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.

Finally, we shall determine the mass of Cu produced by the reaction of 780 g of CuSO₄. This can be obtained as follow:

From the balanced equation above,

159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.

Therefore, 780 g of CuSO₄ will react to produce = (780 × 63.5)/159.5 = 310.53 g of Cu.

Thus, 310.53 g of Cu were obtained from the reaction.

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3 years ago
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Explanation:

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3 0
3 years ago
How many milliliters of .085 m naoh are required to titrate 25 ml of .072 m hbr to the equivalence point?
SOVA2 [1]
The ML  of 0.85  m NaOH    required   to  titrate  25 ml of  0.72m hbr  to  the  equivalence  point  is calculated  as  follows

calculate  the moles  of HBr used

moles  = molarity  x  volume

25  x0.072/1000=  0.0018 moles


write the  equation  for  reaction

NaOH + HBr = NaBr  +  H2O
from   reacting   equation the  mole ratio  between  NaOH  to  HBr  is  1:1  therefore  the  moles of  NaOH  =  0.0018 moles

volume   =  moles/molarity
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I think its potassium
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