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vazorg [7]
3 years ago
14

Both white phosphorus and red phosphorus are made up only of phosphorus atoms.Does this mean they are both pure substances? Coul

d they be compounds?
Chemistry
1 answer:
choli [55]3 years ago
4 0
True, both of the red and white phosphorus is a pure substance.

Both red and white phosphorus is made of phosphor element but they have a different structure which causes them to have a different color. This phenomenon called allotropes when a chemical element has two or more different form.They are not compounds as they are only made of phosphorus. A compound should be made by at least two different elements.
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Need help !!!!! ASAP
Nat2105 [25]
<h2>Hello!</h2>

The answer is:

The temperature will be the same, 37°C.

<h2>Why?</h2>

Since from the statemet we know the first temperature, pressure and volumen of a gas, and we need to calculate the new temperature after the pressure and the volume changed, we need to use the Combined Gas Law.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using Boyle's Law, Gay-Lussac's Law and Charles's Law.

The law establishes the following equation:

\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}

Where,

P_{1} is the first pressure.

V_{1} is the first volume.

T_{1} is the first temperature.

P_{2} is the second pressure.

V_{2} is the second volume.

T_{2} is the second temperature.

Then, we are given the following information:

V_{1}=200mL\\P_{1}=4atm\\T_{1}=37\°C\\V_{2}=400mL\\P_{2}=2atm

So, isolating the new temperature and substituting the given information, we have:

\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\T_{2}=P_{2}V{2}*\frac{T_{1}}{P_{1}V_{1}} \\\\T_{2}=2atm*400mL*\frac{37\°C}{4atm*200mL}=37\°C

Hence, we have that the temperature will not change because both pressure and volume decreased and increased proportionally, creating the same relationship that we had before the experiment started.

The temperature will be the same, 37°C

Have a nice day!

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