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dimulka [17.4K]
3 years ago
14

Calculate the density of chloroform

Chemistry
1 answer:
Rina8888 [55]3 years ago
5 0

Answer: The density of chloroform is 1.47 g/mL

Explanation : Given,

Volume = 40.5 mL

Mass of cylinder = 85.16 g

Mass of cylinder and liquid = 145.10 g

First we have to calculate the mass of liquid (chloroform).

Mass of liquid = Mass of cylinder and liquid - Mass of cylinder

Mass of liquid = 145.10 g - 85.6 g

Mass of liquid = 59.5 g

Now we have to calculate the density of liquid (chloroform).

Formula used:

Density=\frac{Mass}{Volume}

Now putting g all the given values in this formula, we get:

Density=\frac{59.5g}{40.5mL}

Density=1.47g/mL

Therefore, the density of chloroform is 1.47 g/mL

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If 6.02×1023 atoms of element Y have a mass of 28.09 g, what is the identity of Y?
Mazyrski [523]

Silicon is the element having a mass of 28.09 g

<u>Explanation</u>:

  • Silicon is the element having an atomic mass of 28.09 g / mol. So 28.09 g of silicon contains 6.023 \times 10^23 atoms. One mole of each element can produce one mole of compound.
  • The Atomic weight of an element can be determined by the number of protons and neutrons present in one atom of that element. So atomic weight expressed in grams always contain the same number of atoms( 6.023 \times10^23).
  • Avagadro number is the number of atoms of 1 mole of any gas at standard temperature and pressure. It has been determined that 6.023 \times 10^23 atoms of an element are equal to the average atomic mass of that element.
8 0
3 years ago
HELP ASAP PLEASAE!!!
N76 [4]

I believe the answer is A. However, I would double check the formula.

4 0
3 years ago
Hydrogen gas was collected by water displacement. what was pressure of the h2 collected if the temperature was 26°c?
Vedmedyk [2.9K]
The ideal gas law may be written as
p= \frac{\rho R T}{M}
where
p = pressure
ρ =density
T = temperature
M = molar mass
R = 8.314 J/(mol-K)

For the given problem,
ρ = 0.09 g/L = 0.09 kg/m³
T = 26°C = 26+273 K = 299 K
M = 1.008 g/mol = 1.008 x 10⁻³ kg/mol

Therefore
p= \frac{(0.09 \, kg/m^{3})*(8.314 \, J/(mol-K))*(299 \, K)}{1.008 \times 10^{-3} \, kg/mol} =2.2195 \times 10^{5} \, Pa

Note that 1 atm = 101325 Pa
Therefore
p = 2.2195 x 10⁵ Pa
   = 221.95 kPa 
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   = 2.19 atm

Answer:
2.2195 x 10⁵ Pa (or 221.95 kPa or 2.19 atm)

4 0
3 years ago
Which description is true of 0.02 M Ca(OH)2 if Ca(OH)2 completely dissociates in water? A. It’s a dilute strong acid. B. It’s a
Sphinxa [80]

Answer: B. It’s a dilute strong base.


Explanation:


1) Definition of acids and bases: as per Bronsted-Lowry model, an acid is a substance that donates hydrogen ions and a base is a substance that accepts hydrogen ions.

Ca(OH)₂ does not have hydrogen ions to donate, but it can accept hydrogen ions to form H₂O according to this equation: H⁺ + OH⁻ → H₂O.

Hence,  Ca(OH)₂ is a base.


2) Definition of strong base: a strong base is a base that dissociates completely into metallic and hydroxide ions in aqueous solutions, while a weak base dissociates partially.


Hence, Ca(OH)₂ is a strong base.


3) Definition of dilute: it refers to a solution meaning that the substance is not pure and the concentration is low. Since, the solution the Ca(OH)₂ is 0.02 M means that it is dilute.


Therefore, we have found that the description of 0.02 M Ca(OH)₂ is that is is a dilute strong base (option B).


5 0
3 years ago
How many grams of CO2 are produced from 51 g of CH4
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Answer:

use the equation Mass= RFM*Moles

Explanation:

use your periodic table

and create a little table

3 0
3 years ago
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