The molarity of the HCl acid will be 0.001 M.
<h3>What is Neutralization ?</h3>
A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H⁺ ions and OH⁻ ions to generate water.
This is the neutralization of a strong acid (HCl) and a strong base (NaOH), which is ruled by this equation :
HCl (aq) + NaOH (aq) → NaCl (aq) + H₂O (l)
Mole Ratio : 1 mol HCl : 1 mol NaOH
Formula used ;
Molarity = number of moles / Volume (in liters)
Solve for n ;
n = M × V
Substitute values and compute ;
n = 0.40 M × 0.025 liter = 0.01 moles NaOH.
As the molar ratio is NaOH : HCl
Therefore, there will be same number mole for the HCl
Now, Molarity of HCl Solution ;
Molarity = n / volume
Molarity = 0.01 / 10
= 0.001 M HCl
Hence, The molarity of the HCl acid will be 0.001 M.
Learn more about neutralization here ;
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