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lianna [129]
4 years ago
8

PLEASE HELP!!!

Physics
1 answer:
iogann1982 [59]4 years ago
5 0
You’re going to use the formulae, mgh( mass x gravity on Earth x height). In your question the answer is gonna be like this:
GPE= mgh= 25x10x3= 38 J
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Consider the system consisting of the box and the spring, but not Earth. How does the energy of the system when the spring is fu
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Answer:

the energy when it reaches the ground is equal to the energy when the spring is compressed.

Explanation:

For this comparison let's use the conservation of energy theorem.

Starting point. Compressed spring

         Em₀ = K_e = ½ k x²

Final point. When the box hits the ground

         Em_f = K = ½ m v²

since friction is zero, energy is conserved

          Em₀ = Em_f

          1 / 2k x² = ½ m v²

          v = \sqrt{ \frac{k}{m} }     x

Therefore, the energy when it reaches the ground is equal to the energy when the spring is compressed.

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