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scZoUnD [109]
4 years ago
5

A woman is sitting at a bus stop when an ambulance with a siren wailing at 317 Hz approaches at 69 miles per hour (mph). Assume

the speed of sound to be 343 m/s. a) How fast is the ambulance moving in meters per second? (perform the necessary unit conversion) Vs= 69 mph = m/s b) What frequency does the woman hear? fa = Hz c) What speed (vs) would the ambulance be traveling in order for the woman to hear the siren at an approaching frequency of 350 Hz? Vs= m/s d) What frequency would she hear as the siren moves away from her at the same speed (as in part c)? fa = Hz
Physics
1 answer:
xxMikexx [17]4 years ago
3 0

Answer:

a) 30.84m/s

b) 348.32Hz

c) 32.34m/s

d) 289.69Hz

Explanation:

a) If 1 mile=1609,34m, and 1 hour=3600 seconds, then 69mph=69*1609.34m/3600s=30.84m/s

b) Based on Doppler effect:

/*I will take as positive direction the vector \vec r_{observer}-\vec r_{emiter} */

f_{observed}=(\frac{v_{sound}-v_{observed}}{v_{sound}-v_{emited}})f_{emited}

f_{observed}=(\frac{343m/s-0m/s}{343m/s-30.84m/s})317Hz=348.32Hz

c) 350Hz=(\frac{343m/s-0m/s}{343m/s-v_{ambulance}})317Hz, V_{ambulance}=343m/s-\frac{317Hz}{350Hz}.343m/s=32.34m/s

d) f_{observed}=(\frac{343m/s-0m/s}{343m/s+32.34m/s})317Hz=289.69Hz

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A bicycle wheel is rotating at 50 rpm when the cyclist begins to pedal harder, giving the wheel a constant angular acceleration
aleksandr82 [10.1K]

Answer:

3.025 revolutions

Explanation:

To solve this question firstly we need to calculate the time t

Given the angular velocity and the angular acceleration

The time t = angular velocity/angular acceleration

Converting 50rpm to rad/s

= 50 × 2π /60

=1.67 rad/s

t = 1.67/0.46

t =3.63s

The wheel makes 50 revolutions in one minute

Therefore in 3.63s, it will make

3.63 × 50/60

= 181.5/60

=3.025 revolutions

Approximately 3 revolutions

3 0
3 years ago
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kozerog [31]

Newton's second equation of motion :-

S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]

This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.

So let's see what pieces of information (bundles of equations) do we have with us, initially.

We have, a very primary equation with us,

dS/dt = v… (I)

(Considering motion in a straight line only)

And we also have the equation

dv/dt = a…(II)

Simply replacing the v in eqn (II) by eqn (I), we find

d2S/dt^2 = a…(III)

This is what we need to solve. It's easy.

You know,

d2S/dt^2 = d/dt(dS/dt) = a

⟹ dS/dt = ∫adt = at+c1

Since, dS/dt is the velocity of the particle,

Therefore, at t = 0, dS/dt|t = 0 = u

⟹ u = a∗0 + c1 = c1

⟹ c1 = u

Therefore, dS/dt = u + at

Thus, S = ∫(udt + atdt)

⟹ S = ut + 1/2at^2 +c^2

If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0

This makes S = S0 +ut + 1/2at^2

Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),

We get

S = ut + 1/2at^2

Hope it helps :)

5 0
3 years ago
two protons are released from rest when they are 0.750 nm apart (a)what is the maximum speed they will reach ? when does this sp
Keith_Richards [23]

Answer:

And so calculating we get the maximum speed at each proton will reach To be 1.36 Times 10 to the four m the second

8 0
2 years ago
True or False:In a current, electrons will always flow from negative to positive.
DIA [1.3K]
It should be true: electrons low from negative toward positive to negative toward positive because opposite charges attract each other.

I hope this was correct
3 0
3 years ago
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When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq
Sindrei [870]

Answer:

<h2> 0.041kg</h2>

Explanation:

Step one:

given data

initial velocity u= 0m/s

Force F= 443N

time t= 4.3 ms= 0.0043seconds

final velocity v= 45.7m/s

Step two:

Required

mass m

we know that the expression for impulse is given as

Ft=mv

make m subject of the formula

m=Ft/v

substitute we have

m=443*0.0043/45.7

m=1.90/45.7

m=0.04kg

The mass of the ball is 0.041kg

6 0
3 years ago
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