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Lorico [155]
3 years ago
6

A 2.1 ✕ 103-kg car starts from rest at the top of a 5.9-m-long driveway that is inclined at 19° with the horizontal. If an avera

ge friction force of 4.0 ✕ 103 N impedes the motion, find the speed of the car at the bottom of the driveway.
Physics
1 answer:
Lina20 [59]3 years ago
7 0

Answer:

3.9 m/s

Explanation:

We are given that

Mass of car,m=2.1\times 10^3 kg

Initial velocity,u=0

Distance,s=5.9 m

\theta=19^{\circ}

Average friction force,f=4.0\times 10^3 N

We have to find the speed of the car at the bottom of the driveway.

Net force,F_{net}=mgsin\theta-f=2.1\times 10^3\times 9.8sin19-4.0\times 10^3

Where g=9.8 m/s^2

Acceleration,a=\frac{F_{net}}{m}=\frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}

v=\sqrt{2as}

v=\sqrt{2\times \frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}\times 5.9}

v=3.9 m/s

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The magnetic dipole moment of the current loop is  0.025 Am².

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<h3>What is magnetic dipole moment?</h3>

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Two children are throwing a ball back-and-forth straight across the back seat of a car. The ball is being thrown 7 mph relative
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<span>Which electromagnetic waves have the shortest wavelengths and highest frequencies?

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