Given:
1 set requires 4 couples 8 dancers.
Total number of people at a square dance = 250.
To find:
The greatest number of sets possible at the dance.
Solution:
We have,
Total people = 250
1 set = 8 people.
![\text{Number of possible sets}=\dfrac{\text{Total people}}{\text{People required for 1 set}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20possible%20sets%7D%3D%5Cdfrac%7B%5Ctext%7BTotal%20people%7D%7D%7B%5Ctext%7BPeople%20required%20for%201%20set%7D%7D)
![\text{Number of possible sets}=\dfrac{250}{8}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20possible%20sets%7D%3D%5Cdfrac%7B250%7D%7B8%7D)
![\text{Number of possible sets}=31.25](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20possible%20sets%7D%3D31.25)
Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.
![\text{Number of possible sets}\approx 31](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20possible%20sets%7D%5Capprox%2031)
Therefore, the number of possible sets at the dance is 31.
5 · (6 - 1) + 3
= 5·5 + 3
= 25 + 3
= 28
Answer:
332
the reason why I think it's $332 is because if you do 1,994 / 6 then that equals 332 I don't know if you get it right if you do great job if you don't I understand
Answer:
6 nickles
2 dimes 2 nickles
1 quarter 1 nickle 5 pennys