First solve the potential energy of the biker. using the fomula:
PE = mgh
where m is the mass of the object
g is the acceleration due to gravity ( 9.81 m/s2)
h is the height
PE = 96 kg ( 1120 m ) ( 9.81 m/s2)
PE = 1054771.2 J
then power = Work / time
P = 1054771.2 J / ( 120 min ) ( 60 s / 1 min)
P = 146.5 W
Answer:
v2^2 - v1^2 = 2 g s fundamental formula
v2 = v1 + 2 g = v1 + 19.8 increase in velocity in 2 sec
v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76
v1 = (2412.76 - 392) / 39.6 = 51.03
v2 = 51.03 + 19.6 = 70.63
T = 70.63 / .8 = 7.207 sec time to fall height of tower
S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m
(Note v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m
2385 / (2 * 9.8) = 122 m (close to 123.1 as was given
Answer:
Ransom E. Olds was the person who invented assembly line.
The assembly line method was the very first method to be used in automotive sector and was the prototype for which Henry Ford industries had developed his own.
Explanation:
Ransom E. Olds was the person who invented assembly line.
The assembly line method was the very first method to be used in automotive sector and was the prototype for which Henry Ford industries had developed his own. Henry Ford enhanced the design of assembly line through the use of a conveyor system's running platforms.
The assembly line has always been recognized as among the 20th century's greatest inventions. It so profoundly influenced the industrialized world that industries that didn't adopt the trend quickly became extinct and was one of the primary factors that helped to incorporate the automobile into American society.
4.266 m is the radius of the circular path the electron follows.
Given
Speed of electron (v) = 7.5 × 10⁶ m/s
Earth's Magnetic Field (B) = 1 × 10⁻⁵ T
We already know that
Mass of electron (m) = 9.1 × 10⁻³¹ kg
Charge on electron (q) = 1.6 × 10⁻¹⁹ C
According to the formula
Radius of circular path(r) = mass on electron × speed/ Charge × Magnetic field
Radius of circular path(r) = m × v/q × B
Put the values into the formula
r = 9.1 × 10⁻³¹ × 7.5 × 10⁶/ 1.6 × 10⁻¹⁹ × 10⁻⁵
On solving, we get
r = 4.266 m
Hence, 4.266 m is the radius of the circular path the electron follows.
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Answer:
x = 
Explanation:
Let's start the exercise with the definition of a system formed by the projectile and the block, in this case the forces during the collision are internal and the moment is conserved,
initial instant. Just before the crash
p₀ = m v + 4m 0
final instant. Right after the crash, before the block began to move
= (m + 4m) v_{f}
how the moment is preserved
p₀ = p_{f}
m v = 5m v_{f}
v_{f} = v/5
knowing the speed of the system (projectile + block) we can use the relationship between work and energy
W = ΔK
starting point. Just when the projectile + block system starts to move
Em₀ = K = ½ m v_{f}²
final point. When the system is stopped
Em_{f} = 0
The work of the friction force is
W = - fr x
the negative sign is because the friction force opposes the motion, let's use Newton's second law to find the friction force
Y Axis
N- W = 0
N = W = mg
The expression for the friction force is
fr = μ N
substituting
fr = μ mg
W = - μ mg x
using the energy duty ratio
- μ mg x = 0 - ½ m 
x = 
we substitute speed
x =
