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m_a_m_a [10]
3 years ago
5

Problem 4:

Physics
1 answer:
Olegator [25]3 years ago
6 0

Answer:

v2^2 - v1^2 = 2 g s        fundamental formula

v2 = v1 + 2 g    = v1 + 19.8         increase in velocity in 2 sec

v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76

v1 = (2412.76 - 392) / 39.6 = 51.03

v2 = 51.03 + 19.6 = 70.63

T = 70.63 / .8 = 7.207 sec     time to fall height of tower

S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m

(Note  v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m

2385 / (2 * 9.8) = 122 m (close to 123.1    as was given

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Answer:

e. All of the above are projectile

Explanation:

A projectile is an object with motion, aka a non-zero speed. A cannonball throwing straight up, rolling down a slope, rolling off the edge of a tale, thrown through the air have motion. They all have speed and kinetic energy. Therefore they can all be considered a projectile.

5 0
3 years ago
Your teacher wants you to perform an experiment that will demonstrate a chemical property. Which experiment should you choose? A
Dovator [93]

A) Measure the pH of different household chemicals

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To demonstrate a chemical property using an experiment, measuring the pH of different household chemicals will be the best way. The pH is the degree of hydrogen or hydroxyl ion concentration in a solution.

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4 0
3 years ago
Read 2 more answers
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Mice21 [21]

The distance traveled by the hockey player is 0.025 m.

<h3>The principle of conservation of linear momentum;</h3>
  • The principle of conservation of linear momentum states that, the total momentum of an isolated system is always conserved.

The final velocity of the hockey play is calculated by applying the principle of conservation of linear momentum;

m_1v_1 = m_2 v_2\\\\v_1 = \frac{m_2 v_2}{m_1} \\\\v_1 = \frac{0.150 \times 45}{90} \\\\v_1 = 0.075 \ m/s

The time taken for the puck to reach 15 m is calculated as follows;

t = \frac{d}{v} \\\\t = \frac{15\ m}{45 \ m/s} \\\\t = 0.33 \ s

The distance traveled by the hockey player at the calculated time is;

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Learn more about conservation of linear momentum here: brainly.com/question/7538238

4 0
2 years ago
A charge of 1.0 × 10-6 μC is located inside a sphere, 1.25 cm from its center. What is the electric flux through the sphere due
Korvikt [17]

Answer:

\Phi_E=0.11\frac{N\cdot m^2}{C}

Explanation:

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This is identical to the electric flux of a point charge located in the center of the sphere.

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8 0
4 years ago
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6x2=12m
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8 0
4 years ago
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