Answer: The smallest valuest value for<em> k </em>is 10, such that LCM o<em>f k</em> and 6 is 60.
Step-by-step explanation:
We know that, LCM = Least common multiple.
For example : LACM of 12 and 60 is 60.
If LCM of k and 6 is 60.
i.e. the least common multiple of k and 6 is 60.
Since, 10 x 6 = 60.
The smallest valuest value for<em> k </em>should be 10, such that LCM o<em>f k</em> and 6 is 60.
Hence, the smallest value of k is 10.
7x-8 (2) = 12x+8
14x-16 = 12x+8
-12x -12x
2x-16 = 8
+16 +16
2x = 24
÷2 ÷2
x= 12
UV= 7x-8
UV= 7(12)-8
UV= 84-8
UV= 76
14×12=168
24×7=168
168÷60=2 hours and 48 minutes
2 hours and 48 minutes+ 8:00AM=10:48AM
Answer: 10:48AM
Ziad is 30 and marc is 10
Answer:
17.8 cm
Step-by-step explanation:
In the 17 hours between heights of 18.6 cm and 15.2 cm, the candle lost 3.4 cm in height. That is, the height decreased at the rate of ...
(-3.4 cm)/(17 h) = -0.2 cm/h
In the 4 hours between 12 hours and 16 hours of burning time, the candle will have changed its height by (4 h)(-0.2 cm/h) = -0.8 cm.
The height at 16 hours of burning is then 18.6 cm -0.8 cm = 17.8 cm.
