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MatroZZZ [7]
4 years ago
12

Imagine that a space probe could be fired as a projectile from the Earth's surface with an initial speed of 5.52 104 m/s relativ

e to the Sun. What would its speed be when it is very far from the Earth (in m/s)? Ignore atmospheric friction, the effects of other planets, and the rotation of the Earth. (Consider the mass of the Sun in your calculations.)
Physics
1 answer:
Thepotemich [5.8K]4 years ago
4 0

Answer:

v_f = 5.4 \times 10^4 m/s

Explanation:

As per energy conservation we can say

initial total energy of the object at the surface of earth = final total energy of the object at highest height

now we have

U_i = -\frac{GMm}{R} + \frac{1}{2}mv^2

here we know that

M = mass of earth

m = mass of object

R = radius of earth

now when object reached far away from the earth then it will only have kinetic energy

U_f = \frac{1}{2}mv_f^2

now by energy conservation

-\frac{GMm}{R} + \frac{1}{2}mv^2 = = \frac{1}{2}mv_f^2

-\frac{GM}{R} + \frac{1}{2}v^2 = \frac{1}{2}v_f^2

-\frac{(6.67 \times 10^{-11})(5.98\times 10^{24})}{6.37\times 10^6} + \frac{1}{2}(5.52 \times 10^4)^2 = \frac{1}{2}v_f^2

-6.26 \times 10^7 + 1.52 \times 10^8 = \frac{1}{2}v^2

v_f = 5.4 \times 10^4 m/s

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a ship A , steaming in a direction 030° with a steady 12 km/h, sight a ship B. The velocity of B relative to A is 10km/h in a di
pickupchik [31]

Answer: 11 km/h at 339° compass

Explanation:

A sees B moving south at 0 km/h

A is moving north at 12cos30 = 10.392 km/h

Therefore B must be moving north at 10.392 k/h

A is moving east at 12sin30 = 6 km/h

B appears to be moving west at 10 km/h

Therefore B must be moving west at 10 - 6 = 4 km/h

B is moving v = √(4² + 10.392²) = 11.135... 11 km/h

θ = arctan( -4 / 10.392) = -21.05 = 339°

8 0
3 years ago
In an internal combustion engine, heat flow into a gas causes it to <br> .
Sunny_sXe [5.5K]

Answer:

Along path BC of the Otto cycle, heat transfer Qh into the gas occurs at constant volume, causing a further increase in pressure and temperature. This process corresponds to burning fuel in an internal combustion engine, and takes place so rapidly that the volume is nearly constant.

7 0
2 years ago
A 6,000N is applied to a formula one car that weighs 500kg. What is the car's acceleration?
Vesna [10]

Answer:

<h2>12 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question

f = 6000 N

m = 500 kg

We have

a =  \frac{6000}{500}  =  \frac{60}{5}  = 12 \\

We have the final answer as

<h3>12 m/s²</h3>

Hope this helps you

8 0
3 years ago
A small sculpture made of brass (rho brass = 8470 kg/m 3 ) is believed to have a secret central cavity. The weight of the sculpt
GaryK [48]

Answer:

Volume of secret cavity = 4 x 10⁻⁶m³

Explanation:

The weight of the sculpture in air is 15.76 N

Mass of the sculpture = 1.61 kg

Mass = Volume x Density

1.61 = V x 8470

Volume of brass =1.90 x 10⁻⁴ m³

When it is submerged in water, the weight is 13.86 N.

That is

  Weight of sculpture - Weight of water displaced = 13.86 N

  15.76 - Weight of water displaced = 13.86

   Weight of water displaced = 1.9 N

   Mass of water displaced = 0.194 kg

 Mass = Volume x Density

  0.194 = V x 1000

  Volume of water displaced =1.94 x 10⁻⁴ m³

Volume of secret cavity =  Volume of water displaced - Volume of brass material

Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³

7 0
4 years ago
According to Boyle’s Law, when pressure is increased...
klasskru [66]

Boyle's law states that when you "shrink"(change its size) a container the pressure increases so the best answer would be D-volume is decreased.

4 0
3 years ago
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