All categories

4 years ago

Which one of the statements below is true about mechanical waves?

Physics

1 answer:

djverab [1.8K]4 years ago

4 0

Answer:

Both sound and waves

Explanation:

Thank me later

You might be interested in

A small town is located near a body of water, and enjoys cooler temperatures than other areas in the same climate zone. This is

Lapatulllka [165]

C- microclimate or either d- climate zone.

5 0

3 years ago

Read 2 more answers

An iron bolt of mass 51.5 g hangs from a string 33.3 cm long. The top end of the string is fixed. Without touching it, a magnet

In-s [12.5K]

Answer:

Explanation:

Let magnetic force F acts towards right and the string makes an angle of θ with the vertical in equilibrium .Let T be tension in equilibrium

T cos θ = mg

T sin θ = F

Dividing

Tan θ = F / mg

F = mg Tanθ

= 51.5 x 9.8 x 10⁻³ x 26 / 20.8 Tanθ = 26 / 20.8 )

= 630.875 X 10⁻³ N

3 0

3 years ago

A 3 kg block is released from rest to slide down a ramp with friction. The length that the block slides is 2 meters and the angl

Arte-miy333 [17]

Answer:

(a). The acceleration is 3.20 m/s².

(b). The amount of work done by each force is 19.2 J.

(c). The total work done on the block is 19.2 J.

(d). The final speed of the block is 6.26 m/s.

Explanation:

Given that,

Mass of block = 3 kg

Distance = 2 m

Angle = 30°

Coefficient of kinetic friction = 0.20

(a). We need to calculate the acceleration

Using balance equation of force

$N = mg\co\theta$

$mg\sin\theta-f_{k}=ma$

$a = g\sin\theta-\mu g\cos30$

Put the value into the formula

$a=g(\sin30-0.20\cos30)$

$a=9.8(\dfrac{1}{2}-0.20\times\dfrac{\sqrt{3}}{2})$

$a=3.20\ m/s^2$

The acceleration is 3.20 m/s².

(b). We need to calculate the amount of work done by each force

Using formula of work done

Normal force is

$N = mg\cos30$

So due to this the net force is zero then the no work done by reaction force.

By another force,

$W= F\times d$

$W=ma\times d$

Put the value into the formula

$W= 3\times3.20\times2$

$W=19.2\ J$

The amount of work done by each force is 19.2 J.

(c). We need to calculate the total work done on the block

The total work done on the block is 19.2 J.

(d). We need to calculate the final speed of the block

Using equation of motion

$v^2=u^2+2gs$

Put the value into the formula

$v^2=0+2\times9.8\times2$

$v=\sqrt{2\times9.8\times2}$

$v=6.26\ m/s$

The final speed of the block is 6.26 m/s.

Hence, This is the required solution.

4 0

3 years ago

8. The amount of water pressure you experience while swimm

Nana76 [90]

Answer: the area of the pool.

Explanation:

3 0

3 years ago

Let's practice calculating the frictional force of a skier on old "woody" skis and wet snow. The skier has a mass of 58 kg. The

kicyunya [14]

Answer:

Kinetic frictional force will be equal to 56.84 N

Explanation:

We have given mass of the skier m = 58 kg

Acceleration due to gravity $g=9.8m/sec^2$

Coefficient of kinetic friction $\mu _k=0.1$

We have to find the kinetic frictional force

Kinetic frictional force is given by

$F_K=\mu _Kmg=0.1\times 58\times 9.8=56.84N$

So kinetic frictional force will be equal to 56.84 N

8 0

4 years ago