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3 years ago

What is temperature?

Physics

1 answer:

FromTheMoon [43]3 years ago

8 0

Answer:

B a measure of the amount of matter in an object

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The ____ is a unique cabling system that allows one cable to be adapted to various services through the use of interchangeable m

olganol [36]

Answer:

ACO cable mate

Explanation:

5 0

3 years ago

Jared walks 120 m east, 150 m south, and then 40 m west. Find the total

shusha [124]

Answer:

310 m

Explanation:

120+150+40=310

4 0

3 years ago

If the coefficient of kinetic friction between a 22 kg kg crate and the floor is 0.27, what horizontal force is required to move

alina1380 [7]

Answer:

58.27 N

Explanation:

the data we have is:

mass: $m=22kg$

coefficient of friction: $\mu =0.27$

and we also know the acceleration of gravity is $g=9.81m/s^2$

We need to do an analysis of horizontal and vertical forces acting on the object:

-------

Vertically the forces acting on the object:

Normal force $N$ (acting up from the object)

weight: $w=mg$ (acting down from)

so the sum of forces in the vertical axis "y" are:

$F_{y}=N-w\\F_{y}=N-mg$

from Newton's second Law we know that $F=ma$ , so:

$ma_{y}=N-mg$

and since the object is not accelerating in the vertical direction (the movement is only horizontal) $a_{y}=0$ , and:

$0=N-mg\\N=mg$

-----------

now let's analyze the horizontal forces

frictional force: $f= \mu N$ and since $N=mg$ --> $f=\mu mg$

force to move the object: $F$

and the two forces just mentioned must be opposite, thus the sum of forces in the "x" axis is:

$F=ma_{x}=F-f\\ma_{x}=F-\mu mg$

and we are told that the crate moves at a steady speed, thus there is no acceleration: $a_{x}=0$

and we get:

$0=F-\mu mg\\F=\mu mg$

substituting known values:

$F=(0.27)(22kg)(9.81m/s^2)\\F=58.27N$

3 0

3 years ago

Whats a observation?

Mumz [18]

When u look at something and study it

7 0

3 years ago

Suppose that it takes 0.6 seconds for a mass on a spring to move from its highest position to its lowest position. What is the p

o-na [289]

The mass on the spring is bouncing.

We would call it a wave-like motion, except that it all stays in the same place. But, just like a wave, moving from the highest position to the lowest position
is one-half of a full wiggle.

(The other half consists of moving from the lowest position back up to the
highest position, where it started from.

So, half of the wave-like motion takes 0.6 seconds.

A full cycle of the wave motion ... the actual period of the bounce,
is double that much time . . .
1.2 seconds.

6 0

4 years ago