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Lady bird [3.3K]
3 years ago
12

White phosphorus, P4, is prepared by fusing

Chemistry
1 answer:
damaskus [11]3 years ago
3 0
2Ca3(PO4)2 + 6SiO2 + 10C ---> P4 + 6CaSiO3 + 10CO

1 mole of Ca3(PO4)2 = 310g
1 mole of P4 = 124g

according to the reaction:
2*310g Ca3(PO4)2----------------124g P4
x g Ca3(PO4)2 ------------------------ 30g P4
x = 150g Ca3(PO4)2

so, your answer is good
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Air in a closed cylinder is heated from 25 degree to 36 degree. If the initial pressure is 3.80 atm what is the final pressure ?
aleksklad [387]
Aww man, I love these types of problems!!!
So, it's a simple formula:
P1*V1/T1=P2*V2/T2

In this case, we remove V(volume) as there is none listed, leaving this:
P1/T1=P2=T2

Think you got it from here? All you gotta do is plug in the numbers and solve
If you have any further problems, just let me know!!
3 0
3 years ago
Read 2 more answers
HELP!
MAVERICK [17]

Answer:

C

Explanation:

energy cannot be created or destroyed like solar energy for instance. it is already energy because it comes from the sun and for other reason.

Hope this helps!

4 0
3 years ago
Which element is in the same family as Chlorine (Cl) and Fluorine (F)?
ValentinkaMS [17]

Answer/Explanation:

Chlorine and Fluorine are in the Halogen family. The elements in the Halogen family are:

Fluorine (F)

Chlorine (Cl)

Bromine (Br)

Iodine (I)

Astatine (At)

Tennessine (Ts)

Hydrogen (H) is a nonmetal

Oxygen (O) is a nonmetal

Lithium (Li) is an alkaline metal.

8 0
3 years ago
Read 2 more answers
What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.
koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>

We have this data:

  • 1.000 mol salt is equal to 58.44 g salt
  • 1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

  • 1 L = 1dm³
  • 1 m³ = 10³ dm³

We can use proportions:

10.0m^{3} .\frac{10^{3}dm^{3}  }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt

8 0
3 years ago
2Al + 3Br2 --&gt; 2AlBr3
vlada-n [284]
A) The limiting reactant is Al
b) Br2 is the excess reactant
c) The amount moles of AlBr3 that get produced will be equal to the number of moles of Al to begin with.
d) 0
4 0
3 years ago
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