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Radda [10]
4 years ago
13

Describing physical and chemical changes:

Chemistry
1 answer:
svetoff [14.1K]4 years ago
8 0
Physical: The chemist could try to bend it to find out how malleable it is. He could also try to pull it into wires to find out how ductile it is.

Chemical: The chemist could put the metal into contact with other substances to get an idea of how reactive it is, and he could try to burn it and find out how flammable it is.
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Explain how creativity can play a role in the construction of scientific questions and hypotheses.
sweet-ann [11.9K]
Scientific questions and hypotheses come up frequently while one is engaged in investigating a scientific phenomenon such  as natural geological phenomena as may occur in geological mapping in the field. For example, there may be a question does this canyon or deeply incised valley which is quite straight follow a weakness in the earth's crust like a major fault or the direction of bedding in well bedded sedimentary rocks. In a particular topographic area, some hypotheses which may be developed is that valleys follow geological structure whereas ridges follow resistant rocks like quartzites or quartz sandstones or in the ocean, points or capes may represent resistant quartz sandstones and bays may represent weak soft shales recessively weathering
4 0
3 years ago
Aristotle provided a system to (blank) the elements.
Lena [83]

Explanation:

xmzfktxtosktaraitkakyssyotiatiaztitj5ia5iatos6ps

8 0
3 years ago
The brightness of a star is determined by _____.
Travka [436]

Answer:

Size and Temperature or E & B

Explanation:

7 0
2 years ago
Read 2 more answers
The standard enthalpy of formation for glucose [c6h12o6(s)] is −1273.3 kj/mol. what is the correct formation equation correspond
balu736 [363]
The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is 
     C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is 
     6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)

Using the equation for the standard enthalpy change of formation 
     ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
     ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}

C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
     ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
                           = -1273.3 - (0 + 0 + 0)
                           = -1273.3
8 0
3 years ago
Which of the following statements is not true regarding acids? (3 points)
horsena [70]

Answer:

Lewis acid is a substance that donates a lone-pair of electrons.

Explanation:

What is said in the statement corresponds to a Lewis base, not an acid. For example, NH3 is a Lewis base, since it is capable of donating its pair of electrons. Trimethylborane (Me3B) is a Lewis acid, since it is capable of accepting a solitary pair.

8 0
4 years ago
Read 2 more answers
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