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labwork [276]
3 years ago
9

12.5% is what in fraction form?

Mathematics
2 answers:
Serggg [28]3 years ago
8 0
1/8 is the answer because when you turn 12.5% into a decimal it is .125 and .125 x 8= 1. Hope this helps you out.
dezoksy [38]3 years ago
4 0
12.5 % as a fraction:

12.5 = \frac{12.5}{100} = 0.125

The largest common multiple is 12.5

\frac{12.5/12.5}{100/12.5} 
\frac{1}{8}

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Is 14 a solution for the equation -5 + 2x = 23? Explain.
Mila [183]

Answer:

Yes because after solving the equation, x does indeed equal 14.

Step-by-step explanation:

-5 + 2x = 23

2x = 23 + 5

2x = 28

x = 14

8 0
2 years ago
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Find h(x) +g(x). h(x)=x^2+6x and g(x)=-2x-3
AURORKA [14]

Answer:

h(x) + g(x) = x^{2} + 4x - 3

Step-by-step explanation:

h(x) + g(x) = (x^{2} + 6x) + (-2x - 3)

x^{2} + 4x - 3

3 0
2 years ago
in a right triangle, the 58cm hypotenuse makes a 51 angle with one of the legs. rounded to two decimals places, how long is that
ser-zykov [4K]

Answer:

36.50

To two decimal places

Step-by-step explanation:

The hypothenuse side in a right angle triangle has 58cm. While the angle touching one of its leg is 51°. How long is that leg.

From the right angled triangle, the size of the leg touching the hypothenuse is the adjacent side of the triangle, hence in trigonometry, the cosine rule is used, because it involves the adjacent and the hypotenuse.

Cos 51°=x/58

Let the size of the leg be x

Making x the subject

x=58(Cos51°)

x=36.500058

Correct to two decimal place

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3 0
3 years ago
Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and ob
klio [65]

Answer:

Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.

A.  The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.

B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.

C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.

D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.

E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake

The answer is E.

6 0
3 years ago
12 is what percent of 10
Delicious77 [7]
Your answer is 1.2.


I hope I helped you! :)
5 0
3 years ago
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