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labwork [276]
3 years ago
9

12.5% is what in fraction form?

Mathematics
2 answers:
Serggg [28]3 years ago
8 0
1/8 is the answer because when you turn 12.5% into a decimal it is .125 and .125 x 8= 1. Hope this helps you out.
dezoksy [38]3 years ago
4 0
12.5 % as a fraction:

12.5 = \frac{12.5}{100} = 0.125

The largest common multiple is 12.5

\frac{12.5/12.5}{100/12.5} 
\frac{1}{8}

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0.0000075 = 7.5 x 10^6 --- Patients Blood

and it has to be between 0.0000006 and 0.000016

so <em>Yes</em> it is normal
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What is the relationship between A: Vertical angles <br> B: Complementary angles <br> C: Supplementary angles <br> D: None of th
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B. Complementary Angles

Step-by-step explanation:

They both make up 90 degree angle.

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Find the complex zeros of <br><img src="https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20%7Bx%7D%5E%7B3%20%7D%20%20-%2013%20%7Bx%7D%5
timama [110]

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6 0
3 years ago
Is 1/3x-2y=7 a linear function
Ann [662]

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The equation is not a linear function.

5 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
4 years ago
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