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andre [41]
4 years ago
9

How much heavier is an alpha particle than an electron?

Chemistry
2 answers:
Ugo [173]4 years ago
6 0

Answer:

The mass of the alpha particle is approximately 7300 greater than that of electron.

Explanation:

The mass of electron = 9.11\times 10^{-31}\ kg

The mass of the alpha particle = tex]6.64424\times 10^{-27}\ kg[/tex]

Thus, the ratio of the mass of alpha particle and mass of electron is:

\frac{m_{alpha\ particle}}{m_{electron}}=\frac{6.64424\times 10^{-27}}{9.11\times 10^{-31}}

\frac{m_{alpha\ particle}}{m_{electron}}=7293.35\cong 7300

So,

The mass of the alpha particle is approximately 7300 greater than that of electron.

grandymaker [24]4 years ago
4 0
An electron weighs 1/1836 atomic mass unit and, on the other hand, an alpha particle weighs 4 atomic mass unit.

<span>4 amu / (1/1836 amu) = 7344 </span>

<span>Therefore, an alpha particle is 7344 times heavier than an electron. 

Hope this answers the question. Have a nice day.</span>
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Briefly explain formality in solution.
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To aid in the prevention of tooth decay, it is recommended that drinking water contains 0.900 ppm fluoride (F-). A) How many g o
Romashka-Z-Leto [24]

Answer:

a) <u>1.740 g</u> of F- must be added to a cylindrical water reservoir

b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

\pi  r^{2}h ,

Here r = radius of the cylinder = d/2

h = depth = 21.80m

r=\frac{d}{2}

=\frac{3.36x10^{2}}{2}

= 168 m

Volume =

=\frac{22\times 168^{2}\times 21.80}{7}

=1.93\times 10^{6} m^{3}

2.Convert ppm to g/m3 and Solve for mass of F-

1ppm = 1g/m^{3}

0.9ppm = 0.9g/m^{3}

Because both ppm and g/m3 are same quantity .

g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}

0.9 =\frac{mass\ of\ F-}{1.93\times 10^{6} m^{3}}\times 10^{6}

mass\ of\ F- =1.740g

mass of F- required = 1.740 g

3. Apply <u>mole concept </u>to calculate grams of sodium fluoride produced

mass of 1 mole of F2 = 38 g

mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

2Na+F_{2}\rightarrow 2NaF

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g  of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

\frac {84}{38}\times 1.74

1.74 g F2 produce = 3.84 g of NaF

3.84 g of NaF is produced

3 0
3 years ago
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