Answer:it’s D Brønsted-Lowry base
Explanation:
C₈H₁₈ is a non-electrolyte
Why?
Electrolytes are substances that dissociate into ions when dissolved in water. In order to do that, they need to have bonds that are polar enough to be able to dissociate, and the ions formed need to be soluble in water.
C₈H₁₈ is a compound that has a low electronegativity difference between its atoms, making it to be a covalent compound where electrons are shared, and making it non-polar, and difficult to dissociate. Thus, it is a non-electrolyte.
One possible structure for C₈H₁₈ is attached below. It's called octane.
Have a nice day!
#LearnwithBrainly
For a balance chemical equation:
The number of atoms of a molecule should remain conserved that is total number of atom of a molecule in reactant side should equal to the number of atoms of a molecule in the product side.
Here also the number of atoms of an element should remain conserved on both sides, So the answer is option B.
That is
B) 3CuCl₂ + 2Al ---> 2AlCl₃ + 3Cu
Here the number of atoms of Cu, Cl and Al are equal in both side , reactant as well as product.
Answer:
Matter
Compound
Explanation:
Caffeine is NOT an Element, because it is formed by different elements (C, H, N, and O).
Caffeine is NOT an Isotope, because this only applies to elements with the same atomic number but different mass number.
Caffeine is Matter because it has mass and occupies space by having volume.
Caffeine is a Compound because it has a formula with a <em>definite constant composition</em> of different elements.
We will use this two reaction equation:
H2SO3 + H2O ↔ H3O+ + HSO3- Ka1 = 1.3 x 10^-2
HSO3- + H2O ↔ H3O+ + SO3 2- Ka2= 6.3 x 10^-8
we will use the ICE table for the first equation:
H2SO3 + H2O ↔ H3O+ + HSO3-
initial 0.025 0 0
change -X +X +X
Equ (0.025-X) X X
Ka1 = [H3O+] [HSO3-] / [H2SO3]
1.3 x 10^-2 = X^2 / (0.025 - X) by solving for X
∴ X = 0.0127
when [H3O+] = X
∴[H3O+] = 0.0127 M
and when [HSO3-] = X
∴[HSO3-] = 0.0127 M
and when [H2SO3] = 0.025 - X
∴[H2SO3] = 0.025 - 0.0127
= 0.0123 M
when Kw = [OH-][H3O+]
and Kw = 1.1 x 10^-14 / 0.0127
∴[OH-] = 1.1 x 10^-14 / 0.0127
= 8.66 x 10^-13 M
- by using the ICE table for the second equation:
HSO3- + H2O ↔ H3O+ + SO3 2-
initial 0.0127 0.0127 0
change -X +X +X
Equ (0.0127-X) (0.0127+X) X
when Ka2 = [SO32-] [H3O+] / [HSO3-]
by substitution:
6.3 x 10^-8 = X(0.0127+X) / (0.0127-X)
as the Ka2 is so small so we can assume that (0.01271 + X) & (0.01271-X) = 0.01271 and neglect X
6.3 x 10^-8 = 0.0127X /0.0127
∴X = 6.3 x 10^-8
when [SO3 2-] = X
∴[SO32-] = 6.3 x 10^-8
