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ratelena [41]
3 years ago
15

Word equation for Cu(s)+O2(g)=CuO(s)

Chemistry
2 answers:
Mazyrski [523]3 years ago
7 0

Answer:

Copper solid plus oxygen gas giving solid cupric oxide

Explanation:

The given reaction is:

Cu(s) +O2(g)\rightarrow CuO(s)

The balanced equation is:

2Cu(s) +O2(g)\rightarrow 2CuO(s)

The formula name of the reactants and products are:

Cu (s) = copper in the solid phase

O2 (g) = oxygen in the gas phase

CuO (s) = copper (II) oxide or cupric oxide

The word equation would be:

Copper solid plus oxygen gas giving solid cupric oxide

Ludmilka [50]3 years ago
4 0
Copper + Oxygen = Copper Oxide
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Help pleaseee
marissa [1.9K]

Answer:

In order to find the molecular formula from an empirical formula you must find the ratio of their molecular masses.

We know that the molecular mass of the molecule is 70

gmol-1

. We can calculate the molar mass of

CH2

from the periodic table:

C=12.01

gmol−1

H=1.01

gmol−1

CH2 =14.03

gmol−1

Hence we can find the ratio:

14.03

70

≈

0.2

6 0
3 years ago
2131211.1994 x 102 mL<br> Scientific notation
andreyandreev [35.5K]

Answer:

The answer is 213121119.94. Please mark me brainliest if I helped.

7 0
3 years ago
Examination of a cell by transmission electron microscopy reveals a high density of ribosomes in the cytoplasm. This observation
True [87]

Answer:

The answer is the B. Proteins

Explanation:

It is known that Ribosomes are the factory to synthesize proteins. This is their function.  In cell zones where ribosomes are abundant, proteins are actively produced

3 0
2 years ago
The reactant side of a balanced chemical equation is shown below.
Sloan [31]

Answer:

2

Explanation:

In the equation, Cl is chlorine and there is a number "2" so that the correct answer is 2.

6 0
3 years ago
Read 2 more answers
Nitrogen dioxide reacts with water to form nitric acid and nitrogen monoxide according to the equation: 3NO2(g)+H2O(l)→2HNO3(l)+
Vesnalui [34]

Answer:

2 mol NO2

Explanation:

                                      3NO2(g)+H2O(l)→2HNO3(l)+NO(g)

from reaction                3 mol        1 mol

given                           11 mol          3 mol

for 3 mol NO2  -----   1 mol H2O

for x mol NO2  -----   3 mol H2O

3:x = 1:3

x = 3 *3/1 = 9 mol NO2

So, for 3 mol H2O are needed only 9 mol NO2.

But we have 11 mol NO2. So, NO2 is in excess, and

11 mol NO2 - 9 mol NO2 = 2 mol NO2 will be left after reaction.

3 0
3 years ago
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