Word equation for Cu(s)+O2(g)=CuO(s)

Chemistry

2 answers:

Mazyrski [523]3 years ago

7 0

Answer:

Copper solid plus oxygen gas giving solid cupric oxide

Explanation:

The given reaction is:

$Cu(s) +O2(g)\rightarrow CuO(s)$

The balanced equation is:

$2Cu(s) +O2(g)\rightarrow 2CuO(s)$

The formula name of the reactants and products are:

Cu (s) = copper in the solid phase

O2 (g) = oxygen in the gas phase

CuO (s) = copper (II) oxide or cupric oxide

The word equation would be:

Copper solid plus oxygen gas giving solid cupric oxide

Ludmilka [50]3 years ago

4 0

Copper + Oxygen = Copper Oxide

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A 500.0 g block of dry ice (solid CO2, molar mass = 44.0 g) vaporizes at room temperature. Calculate the volume of gas produced

Damm [24]

Considering the ideal gas law, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

<h3>Definition of ideal gas</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

<h3>Ideal gas law</h3>

An ideal gas is characterized by absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

<h3>Volume of gas</h3>

In this case, you know:

P= 1.50 atm
V= ?
n= 500 g× $\frac{1 mole}{44 g}$ = 11.36 moles, being 44 $\frac{g}{mole}$ the molar mass of CO₂
R= 0.082 $\frac{atmL}{molK}$
T= 25 C= 298 K (being 0 C=273 K)