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kirill [66]
3 years ago
6

If temperature is kept constant and the volume of a gas is doubled, what will happen to the pressure?

Chemistry
1 answer:
Mrrafil [7]3 years ago
5 0

Answer:

pressure = P1/2

Explanation:

using boyles law

P1V1=P2V2

V2 = 2V1

P1V1=P2 x 2V1

P1 = p2 x 2

P2 = P1/2

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Explain how an ionic compound forms from these elements.
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8 0
1 year ago
An object weighing 80 kg floating in a fluid. How does the object's density compared to the density of the fluid
posledela
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6 0
3 years ago
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mamaluj [8]

The structure that corresponds to methylpropylether is the structure CH3 - O - C3H7 in option C.

<h3>What is structure?</h3>

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4 0
2 years ago
A solution is prepared by dissolving 0.56 g of benzoic acid (C6H5CO2H, Ka ???? 6.4 ???? 10????5) in enough water to make 1.0 L o
garri49 [273]

Answer:

[H⁺] = 6.083x10⁻⁴ M, [C₆H₅OO⁻] = 6.083x10⁻⁴ M, [C₆H₅OOH] = 3.98x10⁻³M, pH = 3.22

Explanation:

Data: we have 0.56 gr of benzoic acid, disolved in 1Lt of water. Kₐ = 6.4x10⁻⁵

M (molar mass) of BA (Benzoic Acid) = 122 g/mol

Then, the inicial concentration is 0.56/122 = 4.59x10⁻³ M

We should consider the equation once it reaches the equilibrium:

C₆H₅COOH ⇄ C₆H₅COO⁻ + H⁺

  C - x                      x              x

And, for the Kₐ:

Kₐ = [H⁺][C₆H₅COO⁻]/[C₆H₅COOH] = x²/(C-x) , where C = 4.59x10⁻³

Then: x² + Kₐx - KₐC = 0

x² + 6.4x10⁻⁵ - 2.9x10⁻⁷ = 0

Resolving this cuadratic equation (remember to use Baskara equation), we obtain:

x = 6.083x10⁻⁴ M

Then: [H⁺] = [C₆H₅COO⁻] = 6.083x10⁻⁴ M

[C₆H₅COOH] = C - x = 3.98x10⁻³ M

pH = -Log [H⁺] = 3.22

7 0
3 years ago
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