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1 year ago

The ammonium ion has one nitrogen atom and four hydrogen atoms.

Chemistry

1 answer:

Rainbow [258]1 year ago

5 0

Answer:

1.) NH₄

Explanation:

Atoms are depicted by letters in chemical formulas. Nitrogen atoms are represented by the letter "N" and hydrogen atoms are represented by the letter "H". One letter indicates one atom.

As such, if there is 1 nitrogen atom and 4 hydrogen atoms in ammonium, the chemical formula is NH₄.

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Which of the following is an example of eukaryotic cells?<br> animals<br> bacteria<br> archaea

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Answer:

Animals

Explanation:

Eukaryotic organisms are multi-celled. Animals and plants are a major example of that

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3 years ago

the atomic number of four elements p,q,r,s are 6,8,10 and 12 respectively. the two elements which can bond ionically are:

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Answer:

The atomic numbers of four elements A, B, C, and D are 6,8,10, and 12 respectively. The two elements which can react to form ionic bonds (or ionic compounds) are B (8= 2,6) and D (12 =2,8,2). So D donates its two electrons to B to fulfill their octet.

Explanation:

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2 years ago

If you feed 100 kg of N2 gas and 100 kg of H2 gas into a

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Answer : The mass of ammonia produced can be, 121.429 k

Solution : Given,

Mass of $N_2$ = 100 kg = 100000 g

Mass of $H_2$ = 100 kg = 100000 g

Molar mass of $N_2$ = 28 g/mole

Molar mass of $H_2$ = 2 g/mole

Molar mass of $NH_3$ = 17 g/mole

First we have to calculate the moles of $N_2$ and $H_2$ .

$\text{ Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molar mass of }N_2}=\frac{100000g}{28g/mole}=3571.43moles$

$\text{ Moles of }H_2=\frac{\text{ Mass of }H_2}{\text{ Molar mass of }H_2}=\frac{100000g}{2g/mole}=50000moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2+3H_2\rightarrow 2NH_3$

From the balanced reaction we conclude that

As, 1 mole of $N_2$ react with 3 mole of $H_2$

So, 3571.43 moles of $N_2$ react with $3571.43\times 3=10714.29$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $N_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NH_3$

From the reaction, we conclude that

As, 1 mole of $N_2$ react to give 2 mole of $NH_3$

So, 3571.43 moles of $N_2$ react to give $3571.43\times 2=7142.86$ moles of $NH_3$

Now we have to calculate the mass of $NH_3$

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

$\text{ Mass of }NH_3=(7142.86moles)\times (17g/mole)=121428.62g=121.429kg$

Therefore, the mass of ammonia produced can be, 121.429 kg

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3 years ago

Magnesium reacts with carbon dioxide to form magnesium oxide and pure solid carbon.

guajiro [1.7K]

Answer:

2Mg + 2CO₂ → 2MgO + C

Option a.

Explanation:

The chemical reactions are balanced in order to verify compliance with the Law of conservation of mass. This law states that in any chemical reaction, the mass of the reagents must be equal to the mass of the products

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