How do you know 72/80 is greater than 7/8?
2 answers:
You might be interested in
1331 x³ = 216
x³ = 216/1331
x =![\sqrt[3]{ \frac{216}{1331} } = \frac{6}{11}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B216%7D%7B1331%7D%20%7D%20%3D%20%20%5Cfrac%7B6%7D%7B11%7D%20)
Thank you.
x³ = 216/1331
x =
Thank you.
For this case we must find the solution set of the given inequalities:
Inequality 1:
Applying distributive property on the left side of inequality:
Subtracting 3 from both sides of the inequality:
Dividing by 6 on both sides of the inequality:
Thus, the solution is given by all the values of "x" greater than 3.
Inequality 2:
Subtracting 3x from both sides of the inequality:
Subtracting 3 from both sides of the inequality:
Thus, the solution is given by all values of x less than 4.
The solution set is given by the union of the two solutions, that is, all real numbers.
Answer:
All real numbers
<u>Given</u>:
The given expression is
We need to determine the values for which the domain is restricted.
<u>Restricted values:</u>
Let us determine the values restricted from the domain.
To determine the restricted values from the domain, let us set the denominator the function not equal to zero.
Thus, we have;
Taking square root on both sides, we get;
Thus, the restricted value from the domain is
Hence, Option A is the correct answer.