Answer:
The factors of x² - 3·x - 18, are;
(x - 6), (x + 3)
Step-by-step explanation:
The given quadratic expression is presented as follows;
x² - 3·x - 18
To factorize the given expression, we look for two numbers, which are the constant terms in the factors, such that the sum of the numbers is -3, while the product of the numbers is -18
By examination, we have the numbers -6, and 3, which gives;
-6 + 3 = -3
-6 × 3 = -18
Therefore, we can write;
x² - 3·x - 18 = (x - 6) × (x + 3)
Which gives;
(x - 6) × (x + 3) = x² + 3·x - 6·x - 18 = x² - 3·x - 18
Therefore, the factors of the expression, x² - 3·x - 18, are (x - 6) and (x + 3)
Hello!
Your answer is:
x-31 ≥ 66⇒x ≥ 97!
Hopefully this helps! Please correct me if im wrong! :C
Answer:
342
Step-by-step explanation:
Hope this helpss
942 x .36
3/4b-1/6=1/2×b
1.75b=.3
b=0.2
I believe this is right. But not 100%