Answer:
see below
Step-by-step explanation:
<h3>Proposition:</h3>
Let the diagonals AC and BD of the Parallelogram ABCD intercept at E. It is required to prove AE=CE and DE=BE
<h3>Proof:</h3>
1)The lines AD and BC are parallel and AC their transversal therefore,
![\displaystyle \angle DAC = \angle ACB \\ \ \qquad [\text{ alternate angles theorem}]](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%5Cangle%20DAC%20%3D%20%20%5Cangle%20ACB%20%5C%5C%20%20%5C%20%5Cqquad%20%5B%5Ctext%7B%20alternate%20angles%20theorem%7D%5D)
2)The lines AB and DC are parallel and BD their transversal therefore,
![\displaystyle \angle BD C= \angle ABD \\ \ \qquad [\text{ alternate angles theorem}]](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%5Cangle%20BD%20C%3D%20%20%5Cangle%20ABD%20%5C%5C%20%20%5C%20%5Cqquad%20%5B%5Ctext%7B%20alternate%20angles%20theorem%7D%5D)
3)now in triangle ∆AEB and ∆CED
therefore,
hence,
Proven
Answer:it would be way over 100 because If you do the math it comes out as 312.73….. therefore it’s higher than 100 hope this helped hunny boo
Answer:
-13/2
Step-by-step explanation:
7(y+3)=5y+8
7y+21=5y+8
7y-5y+21=8
2y+21=8
2y=8-21
2y=-13
y=-13/2
45 over 48 because 3 over 8 times 1 over 6 equals 3 over 48 and 48 take away 3 equals 45
Answer:
8+x , x+8
Step-by-step explanation:
5+3 =8
x cannot be simplified since its value is unknown.
8+x or x+8
