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3 years ago

Solve log8(x+2)-log8(x-1)=2/3

Mathematics

1 answer:

Alex17521 [72]3 years ago

7 0

You would simplify it too 2.70927 = 2/3

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The pulse rates, in beats per minute, for some students of a class are shown below:

Crazy boy [7]

Answer:

Put another dot on 79

Step-by-step explanation:

Because the plot shows that 79 must have 4 dot.So you need to add one more dot

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3 years ago

How can you find the lateral area using the perimeter of the base and the height?

DENIUS [597]

You multiply the perimeter of the base by the height of the prism to get the lateral are or. LA=pB*H Lateral Area=perimeter of Base times Height

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3 years ago

Which equation does not represent a function? A) y = 2x + 3 B) x = 4y + 7 C) 6x - 5y = 8 D) y2 = -5x - 8

marin [14]

D. It is not a function because there are multiple outputs for one input.

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3 years ago

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Two ropes are attached to a large ballon in a parade. The people holding the ropes are 40 feet apart,and the angle between the t

tankabanditka [31]

Answer:

We'll use the Law of Sines:

Sine (C) / c = Sine (B) / b

Sine (86) / 40 = Sine (52) / b

0.99756 / 40 = 0.78801 / b

0.024939 = .78801 / b

b = .78801 / .024939

side b = 31.5974978949 feet

Sine (42) / a = Sine (86) / 40

(0.66913 / a) = 0.024939

a = .66913 / .024939

side a = 26.8306668271 feet

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I forgot to include the graphic.

Step-by-step explanation:

8 0

3 years ago

Use theorem 7. 4. 2 to evaluate the given laplace transform. do not evaluate the convolution integral before transforming. (writ

irga5000 [103]

With convolution theorem the equation is proved.

According to the statement

we have given that the equation and we have to evaluate with the convolution theorem.

Then for this purpose, we know that the

A convolution integral is an integral that expresses the amount of overlap of one function as it is shifted over another function.

And the given equation is solved with this given integral.

So, According to this theorem the equation becomes the

$\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{ \mathscr{L} (e^{-\tau} \cos \tau ) }{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{\frac{s+1}{(s+1)^2+1}}{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{1}{s}\left (\frac{s+1}{(s+1)^2+1} \right).$

Then after solving, it become and with theorem it says that the

$\mathscr{L} \left( \int_{0}^{t} f(\tau) d\tau \right) = \frac{\mathscr{L} ( f(\tau))}{s} .$

Hence by this way the given equation with convolution theorem is proved.

So, With convolution theorem the equation is proved.

Learn more about convolution theorem here

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3 0

2 years ago