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2 years ago

Original price: $35 Percent of discount: Sale price: $31.50

Mathematics

1 answer:

AlladinOne [14]2 years ago

6 0

Answer:

ok i agree

Step-by-step explanation:

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Answer, please. I need help.

kumpel [21]

Answer:

2i, if you don't understand any of the steps let me know, I'd be happy to explain.

Step-by-step explanation:

$\sqrt{-x} =\sqrt{-1*x} ,\sqrt{xy}=\sqrt{x} \sqrt{y}, \sqrt{-1}=i$

so in order -4 = -1 * 4 so then $\sqrt{-1*4}=\sqrt{-1} \sqrt{4}$ then just solve each

4 0

2 years ago

Read 2 more answers

Write a definite integral that represents the area of the region. (Do not evaluate the integral.)

joja [24]

Answer:

$\int_{-1}^{1}7(x^{3}-x)\:dx$

Step-by-step explanation:

1) The other curve is $y=0$ then the common points of both curves are x-intercepts, the roots of $y=7(x^{3}-x)$

$y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )$

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

$\int_{a}^{b}|f(x)-g(x)dx$

$\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx$

8 0

2 years ago

What is the method used when the objective is to determine the cause and effect relationship of a certain phenomenon under contr

jenyasd209 [6]

Answer: A

Explaination:
The cause and effect relationship of a certain phenomenon under controlled condition

5 0

1 year ago

The cost price of a article is Rs.300/=. It is sold with 15% profit find the selling price of the article.

jek_recluse [69]

Answer:

sp=100+gain%/100*cp

100+15%/100*300

300*15=inr4500

plz mark me branliest

3 0

2 years ago

Read 2 more answers

What are the solutions of x² + 6x - 16 = 0?

AveGali [126]

Step-by-step explanation:

$x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}}{2\cdot \:1}\\\sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}\\\sqrt{6^2+64}\\\sqrt{36+64}\\\sqrt{100}\\\sqrt{10^2}\\=10\\x_1=\frac{-6+10}{2\cdot \:1},\:x_2=\frac{-6-10}{2\cdot \:1}\\\\\bold{x_1:2}\\\frac{-6+10}{2\cdot \:1}\\\frac{4}{2\cdot \:1}\\\frac{4}{2}\\=2\\\\\bold{x_2:-8}\\\frac{-6-10}{2\cdot \:1}\\\frac{-16}{2\cdot \:1}\\\frac{-16}{2}\\-\frac{16}{2}\\=-8$

Answer:

x₁ = 2

x₂ = -8

6 0

5 months ago