The equivalent expression to the given expression 25x²+16−40x−64y² are; (5x-4)²−64y² and (5x−4−8y)(5x+4+8y)
<h3>Difference of two squares</h3>
According to the question:
- We are required to determine the equivalent expression.
When we try to factorise the given expression systematically; we have;
- 25x²+16−40x−64y² = (25x²+16−40x)−64y²
By the difference of two squares concept;
Therefore, an equivalent expression is; (5x-4)²−64y²
Similarly, (5x-4)²−64y² is the difference of two squares and can be rewritten as; (5x−4−8y)(5x+4+8y)
Hence, we have the suggested expressions as equivalent expressions.
Learn more about equivalent expression:
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Answer:
9km
Step-by-step explanation:
If the distance on the map of 8cm between her house and school is equal to 12km actual distance. This means that each cm on the map represent 1.5km in actual distance (12/8=1.5).
This means that D is equal to 9km actual distance, because if each cm represents 1.5km, then 6 cm represents 9km (6x1.5=9).
Hope this helped!
Let n represent the number. You require
7n - 2n = 55
5n = 55 . . . . . . collect terms
n = 11 . . . . . . . divide by 5
The number is 11.
Answer:
t = Vp / 8
Step-by-step explanation:
Given:
V = 8t/p
Where,
V = volume
t = temperature
p = pressure
solve for temperature, t as a function of volume and pressure, v and p
V = 8t/p
Cross product
V*p = 8t
Vp = 8t
Divide both sides by 8
Vp / 8 = 8t / 8
Vp / 8 = t
Therefore,
t = Vp / 8
That is, temperature = product of volume and pressure divided by 8
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