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alexandr1967 [171]
3 years ago
10

A 25N object is 3metres up. how much potential energy does it have

Physics
1 answer:
skelet666 [1.2K]3 years ago
5 0
We know, U = F * h
U = 25 * 3
U = 75 J

In short, Your Answer would be 75 Joules

Hope this helps!
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A 2.00-kg object traveling east at 20.0 m/s collides with a 3.00-kg object traveling west at 10.0 m/s.
ELEN [110]
Momentum = mass x velocity

Before collision
Momentum 1 = 2 kg x 20 m /s = 40 kg x m/s
Momentum 2 = 3 kg x -10m/s = -30 kg x m/s

After collision
Momentum 1 = 2 kg x -5 m/s = -10 m/s
Momentum 2 = 3 kg x V2 = 3V2

Total momentum before = total momentum after
40 + -30 = -10 + 3V2
V2 = <span>6.67 m/s

Total kinetic energy before
</span><span>= (1/2) [ 2 kg * 20 m/s * 2 + 3 kg * ( -10 m/s) *2 ]
= 550 J
</span>
<span>Total kinetic energy after
</span>= (1/2) [ 2 kg * ( - 5 m/s) * 2 + 3 kg * 6.67 m/s *2 ]
= 91.73 J

Total kinetic energy lost during collision
=<span>550 J - 91.73 J
= 458.27 J</span>

8 0
3 years ago
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Give four importantnce of recycling ​
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Answer:

prevents pollution, reduces the need to harvest new raw materials, saves energy, reduce greenhouse gas

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Science question. What can cause a change in the direction of a magnetic field?
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Answer:

- Whenever current travels through a conductor, a magnetic field is generated. ... Depending on the shape of the conductor, the contour of the magnetic field will vary. ... Click the Reverse button to change the direction of the current flow ... to make a fist (or to wrap around the wire in question) is the direction of ...

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4 0
3 years ago
A wave is moving toward shore with a velocity of 5.0 m/s. If the frequency is 2.5 Hz, what is the wavelength?
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4 years ago
Water with a volume flow rate of 0.001 m3/s, flows inside a horizontal pipe with diameter of 1.2 m. If the pipe length is 10m an
galben [10]

Answer:

\triangle P=1.95*10^{-4}

Explanation:

Mass m=0.001

Diameter d=1.2m

Length l=10m

Generally the equation for Volume flow rate is mathematically given by

 Q=AV

 V=\frac{Q}{\pi/4D^2}

 V=\frac{0.001}{\pi/4(1.2)^2}

 V=8.84*10^{-4}

Generally the equation for Friction factor is mathematically given by

 F=\frac{64}{Re}

Where Re

Re=Reynolds Number

 Re=\frac{pVD}{\mu}

 Re=\frac{1000*8.84*10^{-4}*1.2}{1.002*10^{-3}}

 Re=1040

Therefore

 F=\frac{64}{Re}

 F=\frac{64}{1040}

 F=0.06

Generally the equation for Friction factor is mathematically given by

 Head loss=\frac{fLv^2}{2dg}

 H=\frac{0.06*10*(8.9*10^-4)^2}{2*1.2*9.81}

 H=19.9*10^{-9}

Where

H=\frac{\triangle P}{\rho g}

\triangle P=\frac{19.9*10^{-9}}{10^3*(9.81)}

\triangle P=H*\rho g

\triangle P=1.95*10^{-4}

 

6 0
4 years ago
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