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3 years ago

11

The distance between two consecutive nodes of a standing wave is 21.9 cm. the hand generating the pulses moves up and down throu

gh a complete cycle 2.13 times every 3.65 s. find the velocity of the wave. answer in units of m/s.

1 answer:

aksik [14]3 years ago

8 0

Distance between consecutive nodes is computed as d = lambda / 2 , where 'lambda ' is the wavelength
so that lambda = 2 x d = 2 x 21.9 = 43.8 cm = 0.438 m further frequency n = 1/T = 2.13 / 3.65 = 0.5835 Hz
then speed of wave V = lambda x n = 0.438 x 0.5835 = 0.2556 m/sec = 25.56 cm/sec

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Second Frictional surface has a coeﬃcient $\alpha _2=0.1$

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Generally the work done by the Tunnel is mathematically given as

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$Total energy\ E_t=Initial\ kinetic energy\ K.E*Work done\ by\ tunnel\ W_t$

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$E_c=mgh$

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$E_c=170.52J$

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$E_f=\alpha *m*g*cos\textdegree*d_c$

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$E_f=11.86965942 \approx 12J$

Generally the energy left in the form of mass $Em$ is mathematically given as

$E_m=E_t+E_c+E_f$

$E_m=(768J)-(170.52)-(12)$

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