Star, star system, galaxy, universe.
Answer:
Speed of the proton is ![v=9.31\times 10^6\ m/s](https://tex.z-dn.net/?f=v%3D9.31%5Ctimes%2010%5E6%5C%20m%2Fs)
Explanation:
It is given that,
Magnetic field, B = 1.35 T
Radius of circular path, r = 0.072 m
The centripetal force is balanced by the magnetic force such that,
![\dfrac{mv^2}{r}=qv](https://tex.z-dn.net/?f=%5Cdfrac%7Bmv%5E2%7D%7Br%7D%3Dqv)
![v=\dfrac{qrB}{m}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7BqrB%7D%7Bm%7D)
q and m is the charge and mass of a proton respectively
![v=\dfrac{1.6\times 10^{-19}\times 0.072\times 1.35}{1.67\times 10^{-27}}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%200.072%5Ctimes%201.35%7D%7B1.67%5Ctimes%2010%5E%7B-27%7D%7D)
![v=9.31\times 10^6\ m/s](https://tex.z-dn.net/?f=v%3D9.31%5Ctimes%2010%5E6%5C%20m%2Fs)
So, the speed if the proton is
. Hence, this is the required solution.
Answer:
Option 4. 0.05 J
Solution:
As per the question:
Spring constant, k = 10 N/m
Equilibrium position, x = 0.1 m
Now,
The potential energy of the spring is given by:
![U = \frac{1}{2}kx^{2}](https://tex.z-dn.net/?f=U%20%3D%20%5Cfrac%7B1%7D%7B2%7Dkx%5E%7B2%7D)
And also from the principle of conservation of energy:
KE = U (1)
where
KE = Maximum Kinetic Energy
U = Potential energy
Thus
KE = U = ![\frac{1}{2}kx^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dkx%5E%7B2%7D)
KE = U = ![0.5\times 10\times 0.1^{2} = 0.05\ J](https://tex.z-dn.net/?f=0.5%5Ctimes%2010%5Ctimes%200.1%5E%7B2%7D%20%3D%200.05%5C%20J)
Answer:
2
Explanation:
İf system ideal ( no frictional force )
Fnet=m.a
20=10.a
a=2m/s2
Answer:a 1 10th
b89 10
Explanation:
thats all i know so thank me when yoiu get them right:)