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3 years ago

Correct answer gets 25 points! Help please!

Mathematics

2 answers:

DanielleElmas [232]3 years ago

4 0

We know, the principle equation of line,
y = mx + c
when, x = 0, y = 4, c =?
4 = (-1)(0) + c
c = 4
When, x = 2, y = (-1)(2) + 4 = -2 + 4 = 2
x = 4, y = (-1)(4) + 4 = -4 + 4 = 0
x = 6, y = (-1)(6) + 4 = -6 + 4 = -2

In short, Your Answers would be 2, 0, -2

Hope this helps!

JulsSmile [24]3 years ago

3 0

Y = mx + c

If y = 4, and x = 0, then:

4 = -1 (0) + c

c = 4

If c = 4:

y = -1 (2) + 4

y = -2 +4

y = 2

If you plug in the different values of x in each equation, the answer should be:

2,0,-2

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9 over 3x = 4 over x + 2

Elan Coil [88]

The equation that we have been given is:

$\frac{9}{3x}$ = $\frac{4}{x+2}$

In order to solve for the value of 'x', we'll have to use cross-multiplication.

Cross-multiplication is a method in which the numerator of one fraction is multiplied by the denominator of another fraction that it is equal to.

Let's cross-mutliply the numerators and denominators:

$\frac{9}{3x}$ = $\frac{4}{x+2}$

9*(x+2) = 4*(3x)

Distribute the numbers into the parentheses.

9x + 18 = 12x

Simplify by subtracting both sides by 9x:

9x - 9x + 18 = 12x - 9x

0 + 18 = 3x

18 = 3x

3x = 18

Divide both sides by 3:

$\frac{3x}{3}$ = $\frac{18}{3}$

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3 years ago

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3 years ago

What is two and seven eights as an improper fraction?

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A fast food restaurant sells two sizes of fries, small and large. On Friday they sold 24 fries

mihalych1998 [28]

Answer:

5:1

Step-by-step explanation:

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2 years ago

Identify the quadratic function that contains the points (-1,-4), (0,0) and (2,-10).

KengaRu [80]

Answer:

Hence, the quadratic equation is:

$f(x)=-3x^2+x=-x(3x-1)$

Step-by-step explanation:

Let the quadratic formula be given by:

$f(x)=ax^2+bx+c$

Now we are given the interpolating points and there corresponding values as:

(-1,-4), (0,0) and (2,-10).

this means then x=-1 f(x)=-4

when x=0 then f(x)=0

and when x=2 then f(x)=-10

so we first put x=0

then f(x)=0=c

hence c=0.

now we are left with the function:

$f(x)=ax^2+bx------(1)$

Hence now we put x=-1 in equation (1)

we get:

$f(x)=a-b=-4------(2)$

now we put x=2

$f(x)=4a+2b=-10------(3)$

On solving equation (2) and (3) by elimination we get:

Multiply equation (2) by 2 and add to equation (3) we obtain;

2a-2b= -8

4a+2b= -10

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6a=-18

⇒ a= -3 on dividing both side by 6.

Hence on putting the value of a in equation (2) we get:

b=1

Hence, the quadratic equation is:

$f(x)=-3x^2+x=-x(3x-1)$

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3 years ago