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tekilochka [14]
3 years ago
9

Ann, Mara, Jenny , Tina, and Sue are sisters. Two of the five sisters must help their father

Mathematics
1 answer:
Flauer [41]3 years ago
8 0
Imagine taking from the group of five sisters to fill two slots. To fill the first slot, there are 5 different sisters that could do it. To fill the second slot, there would only be four left to fill the slot since one is in the first slot.

Therefore, there are 5 * 4, or 20 ways the girls can fill 2 slots. Hope this helps! :)
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Write the fraction as an 1/15 equivalent fraction with a denominator of 45.​
Readme [11.4K]

9514 1404 393

Answer:

  3/45

Step-by-step explanation:

To find the numerator, multiply the desired denominator by the fraction.

  x/45 = 1/15

  x = (45)(1/15) = 45/15 = 3

The equivalent fraction is 3/45.

5 0
2 years ago
Evaluate the following expression when x = -5 and y = -12. | 4x^2 - 2y |
juin [17]
The answer to this is -76
6 0
3 years ago
The first term in a geometric series is 64 and the common ratio is 0.75. Find the sum of the first 4 terms in the series.
maks197457 [2]

Answer:

195.25

Step-by-step explanation:

Consider geometric series  S(n) where initial term is a

So S(n)=a+ar^1+...ar^n

Factor out a

S(n)=a(1+r+r^2...+r^n)

Multiply by r

S(n)r=a(r+r^2+r^3...+r^n+r^n+1)

Subtract S(n) from S(n)r

Note that only 1 and rn^1 remain.

S(n)r-S(n)=a(r^n+1  -1)

Factor out S(n)

S(n)(r-1)=a(r^n+1  -1)

The formula now shows S(n)=a(r^n+1  -1)/(r-1)

Now use the formula for the problem

4 0
3 years ago
The median of the values in a data set is y. If 48 were subtracted from each
3241004551 [841]

Answer:

Answer would be D.

8 0
2 years ago
If I roll two six-sides dice, what is the probability that the sum of the numbers that show up on the dice is 3 or less?
liq [111]

Answer:

1/12

Step-by-step explanation:

first we have to find all the possibilities of getting a sum of 3 or less: 1+1 or 1+2 and we count the second combination 2 times because the numbers can be on either of the dices so we have a total of 3 possibilities. all the possible pairimg of dice are 6*6=36 because each dice has 6 sides and we can get either of them. so the probability would be the chance of getting a sum of 3 or less divided by all the diff combination which equals 3/36 or 1/12 which is roughly around 8.3%

4 0
2 years ago
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