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a_sh-v [17]
3 years ago
12

Solve the rational equation x divided by 4 equals x squared divided by quantity x plus 2 end quantity, and check for extraneous

solutions.
Mathematics
2 answers:
____ [38]3 years ago
5 0

Answer:

x = 0, x = 2/3

Step-by-step explanation:

x / 4 = x² / (x + 2)

x = 4x² / (x + 2)

x * (x + 2) = 4x²

x² + 2x = 4x²

3x² - 2x = 0

x(3x - 2) = 0

x = 0, x = 2/3

Norma-Jean [14]3 years ago
5 0

Answer:

x=0, 2/3

Step-by-step explanation:

x/4 = x^2 /(x+2)

Using cross products

4x^2 = x(x+2)

Distribute

4x^2 = x^2 +2x

Subtract x^2 from each side

3x^2 = 2x

Subtract 2x from each side

3x^2 -2x =0

Factor out x

x(3x-2) =0

Using the zero product property

x=0   3x-2 =0

x=0   3x=2

x=0   x= 2/3

Check

x=0

0/4 = 0^2 /(0+2)

0 = 0

Check

x=2/3

(2/3)/4 = (2/3)^2 /((2/3)+2)

1/6 = (4/9)/ (8/3)

1/6 = 4/9 * 3/8

1/6 = 4/8 *3/9

1/6 = 1/6

Both solutions are valid

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Farmer Jane picked 2,552 strawberries. She shared the strawberries among 9 bins. She wrote an equation to find the total number
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D.

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R is remainder and to have equal amounts in each bin she could not put them in one.

3 0
2 years ago
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Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What
777dan777 [17]

Answer:

B) \frac{3}{4} x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

                               = 40 units

Dilating KMPT by a scale factor of \frac{3}{4} would create K'M'P'T' of dimensions; \frac{3}{4} × 12 units by \frac{3}{4} × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

                                  = 2(9 + 6)

                                  = 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be  \frac{3}{4} × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

         perimeter of K'M'P'T' = \frac{3}{4} * x units

                                            = \frac{3}{4}x units

6 0
3 years ago
Find the circumference
tia_tia [17]

Answer:

6.25\pi

Step-by-step explanation:

A circumference of a circle can be determined by this: 2*pi*r

We're given the diameter. Divide that by 2 to get the radius.

6.45/2 = 3.225

Now multiply that by 2*pi. That gives us 2 * 3.14 * 3.225 = 20.253.

This could've also been done easier by doing pi*d where d is the diameter and you give the answer by multiplying them both. Also works, but the above formula is just key to many things and can also be used to derive the simpler one. Hope it helps! :)

7 0
2 years ago
Read 2 more answers
One endpoint of a line segment has coordinates represented by (x+4,1/2y). The midpoint of the line segment is (3,−2).
lesya692 [45]

Answer:

(-x+2, -\frac{1}{2}y-4})

Step-by-step explanation:

We know that one of the endpoints of the line segment is (x+4, 1/2y)

The midpoint of the line segment is (3, -2).

And we want to find the other coordinates in terms of x and y.

To do so, we can use the midpoint formula:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Since we know that the midpoint is (3, -2), let's substitute that for M:

(3, -2)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Let's solve for each coordinate individually:

X-Coordinate:

We have:

3=\frac{x_1+x_2}{2}

We know that one of the endpoints is (x+4, 1/2y). So, let's let (x+4, 1/2y) be our (x₁, y₁). Substitute x+4 for x₁. This yields:

3=\frac{(x+4)+x_2}{2}

Solve for our second x-coordinate x₂. Multiply both sides by 2:

6=x+4+x_2

Subtract 4 from both sides:

2=x+x_2

Subtract x from both sides. Therefore, the x-coordinate of our second point is:

x_2=-x+2

Y-Coordinate:

We have:

-2=\frac{y_1+y_2}{2}

Substitute 1/2y for y₁. This yields:

-2=\frac{\frac{1}{2}y+y_2}{2}

Solve for y₂. Multiply both sides by 2:

-4=\frac{1}{2}y+y_2

Subtract 1/2y from both sides. So:

y_2=-\frac{1}{2}y-4

Therefore, the other coordinate expressed in terms of x and y is:

(-x+2, -\frac{1}{2}y-4})

3 0
3 years ago
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