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Sergio [31]
3 years ago
14

The parent function, f(x) = 5x, has been vertically compressed by a factor of one-half, shifted to the right three units and up

two units.

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

I'm guessing you want to know what the new function looks like.

Compression takes place when you have a function that constant is between 0 and 1

so f(x) = 1/2 5x We'd best not do any more to it for now because it will be altered by the next two transformations.

You want to shift this to the right two units.

That means f(x-2) will bu put into x on the right. You will get

f(x - 2) = 1/2*5(x - 2)

Finally, we want to go up 2 units.  That's done by adding another term on what we have already.

f(x -2)  = 1/2 * 5(x - 2) + 2

A line is not a very good example to be showing these transformations. I'll include a graph.

The red line is f(x) = 5x

The blue line is f(x - 2) = 1/2 * 5(x -2) + 2

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<h2>Hello!</h2>

Since there is no additional information, we can assume that the given angles are respect to the horizontal axis (x), so

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<h2>Why?</h2>

Since there is no additional information about the given angles, we can assume that both angles are respect to the horizontal axis (x), positive direction to x-axis positive directions (right) and above x-axis.

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64.28lbs-46.98lbs=17.3lbs (positive direction)

Fox y-axis forces we have:

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76.60lbs + 17.10 lbs =93.7lbs (positive direction)

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\alpha=tan^{-1}(\frac{y-axisValue}{x-axisValue})=tan^{-1}(\frac{93.7}{17.3})\\\alpha=79.5=80

Hence, the angle between both resultant force components is 80 °, meaning that the resultant force direction is positive, above the x-axis.

Now we have to calculate the magnitude of the resultant force since the sum of both resultant force components is equal to the hypotenuse of the formed triangle, we have that:

sin(\alpha)=\frac{y-axisValue}{ResultantForceMagnitude}=\frac{93.7lbs}{ResultantForceMagnitude}\\\\ResultantForceMagnitude=\frac{93.7lbs}{sin(80)}=95.14lbs

So, we have that:

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Have a nice day!

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