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Alex_Xolod [135]
4 years ago
7

every tenth visitor to an ice cream shop gets free sprinkler. every twelvth visitor gets free hot fudge. which visitor each day

will be the first to get both free sprinkles and free hot fudge?
Mathematics
2 answers:
Vadim26 [7]4 years ago
7 0
The 60th visitor is lcm so ya 6x10 and 12x5
DENIUS [597]4 years ago
4 0


person number 60

10 20 30 40 50<u> 60</u>

12 14 36 48<u> 60</u>

It id in both of their times tables.<u />

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The desired percentage of sio2 in a certain type of aluminous cement is 5.5. to test whether the true average percentage is 5.5
LekaFEV [45]
Given that t<span>he desired percentage of sio2 in a certain type of aluminous cement is 5.5. to test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. suppose that the percentage of sio2 in a sample is normally distributed with σ = 0.32 and that \bar{x}=5.24.

</span>
<span>To investigate whether this indicate conclusively that the true average percentage differs from 5.5.



Part A:

From the question, it is claimed that </span><span>t<span>he desired average percentage of sio2 in a certain type of aluminous cement is 5.5</span></span> and we want to test whether the information from the random sample <span>indicate conclusively that the true average percentage differs from 5.5.

Therefore, the null hypothesis and the alternative hypothesis is given by:

H_0:\mu=5.5 \\  \\ H_a:\mu\neq5.5



Part B:

The test statistics is given by:

z= \frac{\bar{x}-\mu}{\sigma/\sqrt{n}}  \\  \\ =\frac{5.25-5.5}{0.32/\sqrt{16}} \\  \\ = \frac{-0.25}{0.32/4} = -\frac{0.25}{0.08}  \\  \\ =-3.125



Part C:

The p-value is given by

P(z\ \textless \ -3.125)=1-P(z



Part D:

Because the p-value is less than the significant level α, we reject the null hypothesis and conclude that "</span><span>There is sufficient evidence to conclude that the true average percentage differs from the desired percentage."



Part E:

</span>If the true average percentage is μ = 5.6 and a level α = 0.01 test based on n = 16 is used, what is the probability of detecting this departure from H0? (Round your answer to four decimal places.)

The probability of detecting the departure from H_0 is given by

1-\phi\left(z_{1-\frac{\alpha}{2}}+ \frac{\mu_0-\mu_1}{\sigma/\sqrt{n}} \right)+\phi\left(-z_{1-\frac{\alpha}{2}}+ \frac{\mu_0-\mu_1}{\sigma/\sqrt{n}} \right) \\  \\ =1-\phi\left(z_{1-\frac{0.01}{2}}+ \frac{5.5-5.6}{0.32/\sqrt{16}} \right)+\phi\left(-z_{1-\frac{0.01}{2}}+ \frac{5.5-5.6}{0.32/\sqrt{16}} \right) \\  \\ =1-\phi\left(z_{1-0.005}+ \frac{-0.1}{0.32/4} \right)+\phi\left(-z_{1-0.005}+ \frac{-0.1}{0.32/4} \right)

=1-\phi\left(z_{0.995}+ \frac{-0.1}{0.08} \right)+\phi\left(-z_{0.995}+ \frac{-0.1}{0.08} \right) \\  \\ =1-\phi(2.576-1.25)+\phi(-2.576-1.25) \\  \\ =1-\phi(1.326)+\phi(-3.826) \\  \\ =1-0.90758+0.00007 \\  \\ =0.0925



Part F:

What value of n is required to satisfy α = 0.01 and β(5.6) = 0.01? (Round your answer up to the next whole number.)

The value of n is required to satisfy α = 0.01 and β(5.6) = 0.01 is given by

n=\left[ \frac{\sigma(z_{0.005}+z_{0.01})}{\mu_0-\mu} \right]^2 \\  \\ = \left[\frac{0.32(-2.576-2.326)}{5.5-5.6} \right]^2 \\  \\ =\left[\frac{0.32(-4.902)}{-0.1} \right]^2=\left[\frac{-1.56864}{-0.1} \right]^2 \\  \\ =(15.6864)^2=247
3 0
4 years ago
Now suppose that the manufacturer decides to accept the shipment if there is at most one defective part in the sample. How large
Mashcka [7]

Answer:

hello your question is incomplete below is the missing parts of the question

answer : K = 80

Step-by-step explanation:

P [ x ≤ 1 ]  < 0.1

determine how large k have to be

note : n = k

sample proportion = 0.01

E = 0.05 - 0.01 = 0.04

applying this formula below

E = Z_{c} \sqrt{\frac{pq}{n} }  

0.04 = 1.645 \sqrt{\frac{0.05*0.95}{n} }    make n subject of the equation

n = 80.3353

hence  the value of K ≈ 80

4 0
3 years ago
john bought a bicycle for $20 sold it for $30 rebought it for $40 and resold it for $50. How much money did he make or loose?
ValentinkaMS [17]
He lost 50 dollars and earned 80 dollars
7 0
4 years ago
A negative value of r means that:
tatuchka [14]

Answer:

(d.) Those who score high on one variable tend to score low on the other.

Step-by-step explanation:

A negative value of correlation coefficient (r) shows a relationship between two variables such that as one variable increases, the other decreases. It shows the inverse relationship between two variables with the dependence determined by the value of the correlation coefficient (r).

It can be observed that for graphs with negative slope, the correlation coefficient (r) is similarly negative. This speaks about its relationship too.

The correlation coefficient being negative doesn't mean the relationship between the two variables in question is bad, it just means that the correlation relationship is inverse (still dependent). A perfectly negative correlation is -1.  

6 0
3 years ago
a restaurant had 3 full boxes of spoons and 4/6 of a box. If each full box weighed 2 kilograms, what is the combined weight of t
kaheart [24]

Given :

A restaurant had 3 full boxes of spoons and 4/6 of a box.

Each full box weighed 2 kilograms .

To Find :

The combined weight of the boxes the restaurant has.

Solution :

Mass of 1 box is 2 kg .

So , mass of 4/6 of a box is 4/3 kg .

Total mass :

M=3\times \text{Mass of one full box }+ \text{Mass of 4/6 of a box}\\\\M=(3\times 2) + \dfrac{4}{3}\\\\M=7.33\ kg

Therefore ,  the combined weight of the boxes the restaurant has is 7.33 kg.

Hence , this is the required solution .

4 0
4 years ago
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