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Alex_Xolod [135]
3 years ago
10

What is the bond order for the carbon-nitrogen bond in acetonitrile, CH3CN? 2.2.0 03.0.5 C. 3.0 d. 1.5 0.1.0

Chemistry
2 answers:
marin [14]3 years ago
7 0

Answer:

C. 3.0

Explanation:

Bond order is number of the bonding pairs of the electrons between two atoms.

For CH_3CN,

The total number of the valence electrons  = 2(4) + 1(5) + 3(1) = 16

The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,  

The Lewis structure is:

          H

           :                  

H   :    C   :   C   :  :  :   N :

           :

          H

Bond pairs between C and N is 3

<u>So bond pair is 3.</u>

kari74 [83]3 years ago
3 0

Answer:

C. 3.0

Explanation:

To determine the bond order between carbon and nitrogen in acetonitrile, we need to consider the Lewis structure.

N has 5 valence electrons, so it shares 3 pairs of electrons to reach the octet.

C has 4 valence electrons, so it shares 4 pairs of electrons to reach the octet.

As we can see, in the Lewis structure there is a triple bond between C and N. The corresponding bond order is 3.0.

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tensa zangetsu [6.8K]

Answer: a) 1.7\times 10^{-4}

b) 3.4\times 10^{-4}

Explanation:

The reaction is :

2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)

Rate = Rate of disappearance of N_2O_5 = Rate of appearance of NO_2

Rate =  -\frac{d[N_2O_5]}{2dt} = \frac{d[NO_2]}{4dt}

Rate of disappearance of N_2O_5 = \frac{\text {change in concentration}}{time} = \frac{0.100-0.066}{200-0}=1.7\times 10^{-4}

a) Rate of disappearance of N_2O_5 = -\frac{d[N_2O_5]}{2dt}

Rate of appearance of NO_2 = \frac{d[NO_2]}{4dt}

b) Rate of appearance of NO_2 =  \frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}

8 0
3 years ago
The flow of energy through living systems can be modeled as food chains, food webs, or energy pyramids. The energy organisms nee
aliya0001 [1]

Answer:

A.......

Explanation:  The sun is the main source of energy

4 0
3 years ago
When aqueous ammonia is added to a solution containing Bi3+ and Cu2+ cations, ____________ occurs. A. Reduction to black bismuth
MissTica

Answer:

C. Precipitation of white bismuth hydroxide.

Explanation:

When aqueous ammonia is added to a solution that has Bi3+ and CU2+ cations, what we would have as a chemical result is the precipitation of white Bismuth hydroxide.

The chemical reaction for this can be written as,

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Thank you!

6 0
3 years ago
Calculate each of the following:<br> (a) Mass fraction of Cl in calcium chlorate
Marianna [84]

Mass fraction has been the mass of an individual element with respect to the compound. The mass fraction of chloride in calcium chlorate is 0.171.

<h3>What is meant by a mass fraction?</h3>

Mass fraction has been defined as the ratio of the masses of the individual elements present in a compound to the total mass of the molecule or compound.

The formula for a mass fraction (w) is given as,

Mass fraction (w) = mass ÷ total mass

Given,

Mass of chlorine = 35.453 grams per mole

The molar mass of calcium chlorate (Ca(ClO₃)₂) = 206.98 grams per mole

Substituting and solving the values above as

w = mass of chlorine ÷ total mass of calcium chlorate

w = 35.453 ÷ 206.98

w = 0.171

Therefore, the mass fraction of Cl in calcium chlorate is 0.171.

Learn more about mass fraction, here:

brainly.com/question/14470971

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4 0
1 year ago
Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid wat
Makovka662 [10]

Answer:

1.4 g H₂O

Explanation:

In a reaction, the reactants are usually not present in exact <em>stoichiometric amounts</em>, that is, <em>in the proportions indicated by the balanced equation</em>. Frequently a large excess of one reactant is supplied to ensure that the more expensive reactant is completely converted to the desired product. Consequently, some reactant will be left over at the end of the reaction. T<em>he reactant used up first in a reaction</em> is called the <em>limiting reagent</em>, because <u>the maximum amount of product formed depends on how much of this reactant was originally present</u>. When this reactant is used up, no more product can be formed.

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