A specific combination of bonded atoms which always react in the same way, regardless of the particular carbon skeleton is known as the functional group. These are specific groups of atoms or bonds within organic molecules that accounts for the characteristic chemical reactions of those molecules. Examples of functional groups are the Carbonyl group, alkyl Halides, aldehydes and ketones among others.
Answer:
1.26 g of Cu
Explanation:
Since we have to find the percentage of the given amount so...
Yield in grams = (Initial mass used / 100) x Percentage Yield
Yield in grams = (1.57 / 100) x 80.6 = 1.26 g of Cu
The process that took place is called oxidation or burning where wood was burnt into ashes.
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Explanation:</u></h3>
Wood is an organic compound formed of different types of carbohydrates, proteins and lipids. These components do have carbon oxygen hydrogen as most abundant atoms and also has some amount of nitrogen, phosphorous, and other metal ions like magnesium, calcium etc.
When the logs were burnt, the chemical reaction took place between the atmospheric oxygen and the atoms present in the wood, forming different oxides. As carbon was the most abundant atom present, a huge smoke containing carbon dioxide and carbon monoxide evolved. The hydrogen became the water vapour, and other gases were also formed like nitrogen dioxide, sulphur dioxide etc. These gases went off into atmosphere. The rest that were left behind were mixture of unburnt part of wood as well as the solid metal oxides. There were unburnt particles of carbon mixed with them too.
Given data:
Hydrogen (H) = 3.730 % by mass
Carbon (C) = 44.44%
Nitrogen (N) = 51.83 %
This means that if the sample weighs 100 g then:
Mass of H = 3.730 g
Mass of C = 44.44 g
Mass of N = 51.83 g
Now, calculate the # moles of each element:
# moles of H = 3.730 g/ 1 g.mole-1 = 3.730 moles
# moles of C = 44.44/12 = 3.703 moles
# moles of N = 51.83/14 = 3.702 moles
Divide by the lowest # moles:
H = 3.730/3.702 = 1
C = 3.703/3.702 = 1
N = 3.702/3.702 = 1
Empirical Formula = HCN
