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kirill [66]
3 years ago
8

Which of the following is the correct formula for sulfuric acid?

Chemistry
2 answers:
lidiya [134]3 years ago
8 0

Answer : The correct option is, (D) H_2SO_4

Explanation :

Sulfuric acid is a strong acid which is composed of the elements hydrogen, oxygen and sulfur. Sulfuric acid is a colorless and odorless liquid that is soluble in water and it is highly exothermic.

The formation of sulfuric acid from its ions, is given by the equation:

2H^+(aq)+SO_4^{2-}(aq)\rightarrow H_2SO_4(aq)

The molecular formula of sulfuric acid is, H_2SO_4

Hence, the correct formula for sulfuric acid is, H_2SO_4

kondor19780726 [428]3 years ago
6 0
D. H2SO4 would be correct!

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The answer is 5 gold token from Chuck E. Cheese
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Determine the number of moles of air present in 1.35 L at 750 torr and 17.0°C.
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Read 2 more answers
How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?
LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

0.500 L \times \frac{0.360mol}{L} = 0.180 mol

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

0.180 mol \times \frac{110.98g}{mol} = 20.0 g

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0
2 years ago
Which will not appear in the equilibrium constant expression for the reaction below?
n200080 [17]

Answer:

[C] carbon solid

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Pure solids and liquids are never included in the equilibrium constant expression because they do not affect the reactant amount at equilibrium in the reaction, thus since your equation has [C] as solid it will not be part of the equlibrium equation.

5 0
4 years ago
Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0
grandymaker [24]

The given question is incomplete. The complete question is:

Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced

Answer: 60.0 g of glucose

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of CO_2

\text{Number of moles}=\frac{88.0g}{44g/mol}=2.0moles

b) moles of H_2O

\text{Number of moles}=\frac{64.0g}{18g/mol}=3.5moles

6CO_2+6H_2O\rightarrow C_{6}H_{12}O_6+6O_2

According to stoichiometry :

6 moles of CO_2 require = 6 moles of H_2O

Thus 2.0 moles of CO_2 require=\frac{6}{6}\times 2.0=2.0moles  of H_2O

Thus CO_2 is the limiting reagent as it limits the formation of product.

As 6 moles of CO_2 give =  1 moles of glucose

Thus 2.0 moles of CO_2 give =\frac{1}{6}\times 2.0=0.33moles  of glucose

Mass of glucose = moles\times {\text {Molar mass}}=0.33moles\times 180g/mol=60g

Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water  

8 0
3 years ago
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