Let's write the reaction first:
<span>2 Au + 2 BrF</span>₃<span> + 2 KF → 2 KAuF</span>₄<span> + Br</span>₂<span>
</span>
To know which of the substances is the oxidizing agent, calculate the oxidation numbers of each element before and after the reaction. If the element's oxidation number decreases, then that is the oxidation agent. Let's calculate Br.
BrF₃: x + 3(-1) = 0; x = +3
Br₂: 0 (for any elemental form, oxidation number is 0)
The oxidation number is reduced from +3 to 0. <em>Thus, BrF₃ is the oxidizing agent.</em>
Answer:
Numbers of red line are on the right, numbers of blue line are on the left.
Answer:
CaCO3
Explanation:
From the question we were told that Calcium carbonate contains the following:
Ca = 1atom
C = 1atom
O = 3atoms
Combining the above together we will have: CaCO3
The simplest formula for a compound made from element x which is molar mass is equals to 79.0 g/mol that is 21% nitrogen by mass is X sub 2 N sub 3. In addition, X is equals to 79.0 and N is equals to 14.
If this is for chemistry then it's "made up of atoms."
