An ionic bond is a bond between
2 answers:
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Answer: -
0.1 ml of bleach should be added to each liter of test solution.
Explanation:-
Let the volume of bleach to be added is B ml.
Density of stock solution = 1.0 g/ml
Mass of stock solution = Volume of stock x density of stock
= B ml x 1.0 g/ml
= B g
Amount of NaOCl in this stock solution = 5% of B g
= x B g
= 0.05 B g
Now each test solution must be added 5 mg/l NaOCl.
Thus each liter of test solution must have 5 mg.
Thus 0.05 B g = 5 mg
= 0.005 g
B =
= 0.1
Thus 0.1 ml of bleach should be added to each liter of test solution.
Answer: 2.88×atoms
Explanation: First, using stoichiometry, we must convert this from grams to moles, then from moles to atoms.
1. For the first step, we should also look at the periodic table to find the molar mass of the compound, then use that as the denominator.
2. Now that it is converted to moles, we must convert it to atoms by multiplying it by Avogadro's number.
With this information, we know that there are total atoms in 0.680 grams
.
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