Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
It’s just 9 LOL yeahhhhhhhhhhhhhggg hope it goes well lollll
I’m to lazy to figure out this question
Many numbers, when multiplied by

, are less than

. We can find an inequality for numbers

that are sufficient.
Clearly,

is the desired inequality. We divide by 7 to find that

determines working numbers.
3c/5-1/2=-31/2 Add 1/2 both sides
+1/2 +1/2
3c/5=-30/2 Then simplify the fraction
(5)3c/5=-15(5) Multiply 5 both sides
3c=75 Finally, divide by 3 both sides
c=25
So the answer to your question is E.