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mariarad [96]
2 years ago
8

Which of the following describes the dimensions of a backyard?

Mathematics
2 answers:
emmainna [20.7K]2 years ago
8 0

Answer:

the lengths of the sides of the yard.

Step-by-step explanation:

Ad libitum [116K]2 years ago
4 0

Answer:

D

Step-by-step explanation:

this reason is because the sides tell how big your backyard is

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2+2= I NEED HELP<br><br><br> 40 points if you answer
andrew11 [14]

Answer:

4 IS THE ANSWER

BRAINLEST??

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3 years ago
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Consider the differential equation:
Wewaii [24]

(a) Take the Laplace transform of both sides:

2y''(t)+ty'(t)-2y(t)=14

\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s

where the transform of ty'(t) comes from

L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)

This yields the linear ODE,

-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s

Divides both sides by -s:

Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}

Find the integrating factor:

\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C

Multiply both sides of the ODE by e^{3\ln|s|-s^2}=s^3e^{-s^2}:

s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}

The left side condenses into the derivative of a product:

\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}

Integrate both sides and solve for Y(s):

s^3e^{-s^2}Y(s)=7e^{-s^2}+C

Y(s)=\dfrac{7+Ce^{s^2}}{s^3}

(b) Taking the inverse transform of both sides gives

y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that \frac{7t^2}2 is one solution to the original ODE.

y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7

Substitute these into the ODE to see everything checks out:

2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14

5 0
3 years ago
Graph the inequality in the coordinate plane:<br><br> x&lt;-3
tensa zangetsu [6.8K]

Answer:

Graph of the inequality x< -3 as shown below in the figure.

Step-by-step explanation:

Given the inequality: x < -3

Graph of this inequality as shown below in the figure.

All the points that are lie in the shaded area satisfy the equation x < -3 or

In other words, we can say that x can take any value less than -3 .

x ≠ -3 or any number that is greater than -3.

Since there is a strict inequality i.e x < -3 , the points that lie on the line x = -3 does not satisfy the equation.

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2 years ago
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-BARSIC- [3]
I think the answer is G=/2.(8) =(G=4)
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What was Zane's unit rate, in words per minute, on each test?
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Answer:

Test A: 40 words per minute

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<em><u>Test B has the highest unit rate</u></em>

Step-by-step explanation:

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Test B divide 78 by 1\frac{1}{2} (78/1.5=52)

Test C divide 99 by 2\frac{1}{4} (99/2.25=44)

<u>Hope this helps :-)</u>

<u />-noorati<u />

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2 years ago
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